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Tems11 [23]
3 years ago
5

A train travels 50 kilometers in 4 hours, and then 74 kilometers in 2 hours. What is its average speed?

Physics
2 answers:
VladimirAG [237]3 years ago
8 0

If a train travels 50 kilometers in 4 hours, and then 74 kilometers in 2 hours its average speed is 24.75 km / hr.

<u>Explanation:</u>

Speed is related to the ratio of distance and time. Speed = Distance / time.

Speed of the first train = 50 / 4 = 12.5 km / hr

Speed of the second train = 74 / 2 = 3 7 km / hr

Average speed = (12.5 + 3 7 ) / 2 = 24.75 km / hr

So the average speed of the train is 24.75 km / hr.

olga55 [171]3 years ago
4 0

Answer:

37.65

Explanation:

50/4 + 74/2

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The diagram below represents a flashlight that has been turned on. Which form of energy is being converted to electrical energy
Orlov [11]

Answer:

Chemical energy to electrical energy

Explanation:

In nature, there are several types of energy.

In this example (a flashlight being turned on), we have a conversion of energy from chemical energy to electrical energy. In fact:

- Chemical energy is the energy stored in the chemical bonds of the molecules of the substances used inside the battery. When the chemical reaction inside the battery occurs, this energy is liberated, and it is used to "push" the electrons along the circuit connected to the battery

- Electric energy is the energy associated to the motion of the electrons along the circuit of the flashlight; it is the energy associated to an electric current.

Moreover, in the flashlight the electric energy is then converted into two more types of energy: light energy (since the bulb in the flashlight produces light) and heat energy (because the flashlight also produces heat, so thermal energy).

3 0
3 years ago
Alex swims at an average speed of 45m/min. how far does he swim in 1 min 24 sec?
saveliy_v [14]

Answer:

63 m

Explanation:

Average speed of swimming = 45 m/min

Time = 1 minute 24 seconds

Converting time into minutes:

Formula:

Putting values, we get.

Thus, Alex swims for 63 m in 1 minute and 24 seconds.

6 0
3 years ago
The force against a solid object moving through a gas or a liquid
boyakko [2]
This drag force is always opposite to the object's motion, and unlike friction between solid surfaces, the drag force increases as the object moves faster.
3 0
3 years ago
A helium balloon has an internal pressure of 2.5 atm when it occupies 4.5 L. If it was compressed until it had a pressure of 3.3
steposvetlana [31]

Answer: V = 3.4 L

Explanation: Use Boyle's Law to find the new volume. P1V1 = P2V2, derive for V2, then the formula will be V2= P1V1 / P2

V2 = 2.5 atm ( 4.5 L ) / 3.3 atm

= 3.4 L

4 0
3 years ago
Read 2 more answers
Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.
padilas [110]

Explanation:

We have,

Semimajor axis is 4\times 10^{12}\ m

It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :

T^2=\dfrac{4\pi ^2}{GM}a^3

G is universal gravitational constant

M is solar mass

Plugging all the values,

T^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (4\times 10^{12})^3\\\\T=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.98\times10^{30}}\times(4\times10^{12})^{3}}\\\\T=4.37\times 10^9\ s

Since,

1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}

So, the orbital period of a dwarf planet is 138.52 years.

3 0
3 years ago
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