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egoroff_w [7]
4 years ago
5

Fused quartz possesses an exceptionally low coefficient of linear expansion, 5.50 × 10 − 7 ( ∘ C ) − 1 . Suppose a bar of fused

quartz of length 2.99 m at 20.0 ∘ C is heated to 235 ∘ C . By how much, in millimeters, would the bar expand?
Physics
1 answer:
EastWind [94]4 years ago
7 0

To solve this problem it is necessary to apply the concepts related to thermal linear expansion. Mathematically this concept can be expressed under the Equation:

\Delta L = L_0 \alpha \Delta T

Where,

L_0 = Initial Length

\alpha =Thermal Expanssion constant

\Delta T =Change in Lenght

Our values are given as

L_0 = 2.99m

\alpha = 5.50*10^{-7} ( \∘C )^{-1}

\Delta T = T_2-T_1 = 213-20

Replacing at our equation we have,

\Delta L = L_0 \alpha \Delta T

\Delta L = (2.99) (5.5 x 10^{-7}) (213 - 20)

\Delta L = 0.317*10^{-3}m\approx 0.317mm

Therefore the expantion of the bar is 0.317mm

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3 years ago
Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
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Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

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We know that capacitrnce and charge is related as

V = \frac{Q}{C}

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v = 9.523 V

Electric field is given as

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3 years ago
The perimeter of a sector of a circle is the sum of the two sides formed by the radii and the length of the included arc. A sect
snow_tiger [21]

Answer:

Length of the arc of this sector, l = 14 cm

Explanation:

It is given that, the perimeter of a sector of a circle is the sum of the two sides formed by the radii and the length of the included arc.

Perimeter of sector, P = 28 cm

Area of sector, A=49\ cm^2

According to figure,

2r + l = 28 ............(1)

Area of sector, A=\dfrac{\theta}{360}\times \pi r^2

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Since, 1^{\circ}=\dfrac{\pi}{180}\ radian

A=\dfrac{l}{2\pi r}\times \pi r^2

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Put the value of r in equation (1) so,

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On solving above equation for l we get, l = 14 cm. So, the length of the arc of this sector is 14 cm. Hence, this is the required solution.

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