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The magnitude of the change in momentum of the block between zero and 4. 0 seconds is
dp=1.6m/s
<h3>What is the magnitude of the change in momentum of the block between zero and 4. 0 seconds?</h3>
Generally, the equation for the kinematics equation is mathematically given as
x=x+ut+0.5at^2
Therefore
1.6=0+0+0.5*a*1^2
a=0.2m/s^2
In conclusion, change in momentum
dP=mv-mu
2.0*0.8-0
dp=1.6m/s
Read more about Force
brainly.com/question/13370981
Answer: 62.25
Explanation: F = ma
F = 7.5 * 8.3
F = 62.25
Thus, the answer is 62.25 Newtons.
Would appreciate brainliest <3
Answer: A
Explanation:
Parallel circuit. The source current is three times the current of a single bulb
<span>Density can be determined by the
mass of an object and how much it takes up space (volume). It is represented by
the formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the mass
in kg or lb and V is the volume in m^3 or ft^3. The answer would be A. For example, you are given the mass of an
object of 40.5kg and a volume of 15m^3. Find its density.</span>
D = M/V
D = (40.5 kg)
/ (15 m^3)
<span>D = 27/10 or
2.7 kg/m^3 </span>