Answer:
14.14 m/s
Explanation:
As total mechanical energy is conserved, if the potential energy is the same at Chad's position no matter if the ball is travelling up or down, then its kinetic energy, and speed, is also the same too.
Therefore, the ball would have a speed of 10m/s when it's passing Chad the 1st time. Since we know that Chad is at 5m high from the release point, we can use the following equation of motion:
where v = 10 m/s is the velocity of the ball when it passes Chad, v_0 is the initial velocity of the ball when it releases, g = 10 m/s2 is the deceleration of the can, and 
is the distance traveled between Nicole and Chad. We can solve for v0:
Answer:
lol
Explanation:
ok well Jesus considered himself and his disciples fishers of men, so i'd say he swam with the fishies on land everytime he had a mob of people listening lollllll
The ball's vertical velocity at the time it just passes over the goal is 0 m/s. Its initial vertical velocity is unknown and we denote it by 
, where 
here is the ball's initial speed. Vertically, the only force acting on the ball is gravity, which attributes a downward acceleration of 9.8 m/s^2. We expect the maximum height achieved by the ball to be 2.4 m, so we can find the initial speed by solving
A factor of 50dB = a factor of 10^(50/10) = 10^5 = a factor of <em>100,000</em> .
Answer: Because of different redshift of cloud.
Explanation:
We are seeing absorption lines from clouds of gas that lie between us and the quasar, and therefore each cloud has a different redshift.
A quasar's spectrum is hugely redshifted. And most astronomers think this large redshift tells us about the distance to the quasar.
