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3 years ago

CAN SOMEONE ANSWER THIS I DONT GET IT WHERE WILL IT GO?

Physics

1 answer:

nika2105 [10]3 years ago

8 0

Metamorphic to Igneous: Melting and Cooling
Metamorphic to Sedimentary: Erosion and Deposition
Igneous to Metamorphic: Heat and Pressure
Igneous to Sedimentary: Erosion and Deposition
Sedimentary to Metamorphic: Heat and Pressure
Sedimentary to Igneous: Heat and Pressure

<span>I am so sorry if I got it wrong, sometimes I forget the rock cycle. Most likely Sedimemntary to Igneous is wrong.</span>

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$\displaystyle \text{average speed} = \frac{\text{total distance}}{\text{total time}}$ .

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$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{602\; \rm m\cdot s^{-1}} \approx 930\; \rm s$ .

Time required for the second part of this trip:

$\displaystyle \frac{5.60 \times 10^{5}\; \rm m}{903\; \rm m\cdot s^{-1}} \approx 620\; \rm s$ .

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