1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir [108]
3 years ago
10

If the symbol is on the top and bottom of the reference line, we call this __________ sides.

Engineering
1 answer:
sattari [20]3 years ago
6 0
I think the correct answer is B
You might be interested in
Fill in the empty function so that it returns the sum of all the divisors of a number, without including it. A divisor is a numb
tekilochka [14]

Answer:

// Program is written in C++

// Comments are used to explain some lines

// Only the required function is written. The main method is excluded.

#include<bits/stdc++.h>

#include<iostream>

using namespace std;

int divSum(int num)

{

// The next line declares the final result of summation of divisors. The variable declared is also

//initialised to 0

int result = 0;

// find all numbers which divide 'num'

for (int i=2; i<=(num/2); i++)

{

// if 'i' is divisor of 'num'

if (num%i==0)

{

if (i==(num/i))

result += i; //add divisor to result

else

result += (i + num/i); //add divisor to result

}

}

cout<<result+1;

}

6 0
3 years ago
In the LC-3 data path, the output of the address adder goes to both the MARMUX and the PCMUX, potentially causing two very diffe
dangina [55]

Answer:

no need for that

Explanation:

they are not the same at all

3 0
2 years ago
Consider the velocity boundary layer profile for flow over u flat plate to be of the form u = C_1 + C_2 y. Applying appropriate
ra1l [238]

Answer:

The  result in terms of the local Reynolds number ⇒ Re = [μ_∞ · x] / v

Explanation:

See below my full workings so you can compare the results with those obtained from the exact solution.

4 0
3 years ago
A hypereutectoid steel often presents hard and brittle cementite along the grain boundaries of pearlite. Which of the following
Anvisha [2.4K]

Answer:

(d) Spheroidizing

Explanation:

Spheroidizing

 This is the heat treatment process for steel which having carbon percentage more than 0.8 %.As we know that a hard and brittle material is having carbon percentage more than 0.8 %.That is why this process is suitable for the hard materials.

In this process a hard and brittle materials convert into soft and ductile after this it improve the machine ability as well as improve the tool life.

In this process grain become spheroidal and these grains are ductile.

6 0
3 years ago
What is the worlds fastest car
Aneli [31]

Answer:

Thrust SSC

Explanation:

You can look it up

3 0
2 years ago
Read 2 more answers
Other questions:
  • What is the reason for the development of new construction of materials for human use? (Select all that apply.)
    12·1 answer
  • The water behind Hoover Dam is 206m higher than the Colorado river below it. At what rate must water pass through the hydraulic
    15·2 answers
  • A 3-m wide rectangular channel has a flow velocity of 1.8 m/s when the depth of flow is 1.2 m. what will be the flow velocity wh
    14·1 answer
  • Is the COP of a heat pump always larger than 1?
    10·1 answer
  • Technician A says that squeeze-type resistance spot welding (STRSW) may be used on open butt joints. Technician B says that repl
    14·1 answer
  • Explain the underlying physical reason why when we conduct various heat treatments on 1018 steel we expect the modulus of elasti
    8·1 answer
  • Three-dimensional measuring references all of these EXCEPT:
    15·1 answer
  • 2) The switch in the circuit below has been closed a long time. At t=0, it is opened.
    5·1 answer
  • Plssssssssssssss Alexi is writing a program which prompts users to enter their age. Which function should she use?
    5·1 answer
  • Question 1 A design team completes their high-fidelity prototype of a responsive website. Before they hand off designs to the en
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!