Answer:
v_f = 10.85 m/s
Explanation:
We will apply the law of conservation of momentum here:
where,
m₁ = mass of roller skater = 47 kg
m₂ = mass of bag = 6 kg
v_1i = initial speed of roller skater = 12 m/s
v_2i = initial speed of the bag = 0 m/s
v_1f = final speed of the roller skater = ?
v_2f = final speed of the bag = ?
Both the bag and the skater will have same speed at the end because kater is carrying the bag:
v_1f = v_2f = v_f
Therefore, the equation will become:
<u>v_f = 10.85 m/s</u>
Correct question: A uniform magnetic field of 0.25 T points vertically downward. A proton enters the field with a horizontal velocity of 4.0×10⁻² m/s north. What are the magnitude and direction of the instantaneous force exerted on the proton as it enters the magnetic field
Answer:
1.602×10⁻²¹ N west
Explanation:
The force on a charge moving in a magnetic field is given as,
F = Bqv.................. Equation 1
Where F = force on the proton, B = magnetic Field, q = charge of the proton, v = velocity of the proton.
Given: B = 0.25 T, v = 4.0×10⁻² m/s, q = 1.602 x 10⁻¹⁹ C
Substitute into equation 2
F = 0.25(4.0×10⁻²)(1.602 x 10⁻¹⁹)
F = 1.602×10⁻²¹ N
Hence the magnitude and direction of the instantaneous force = 1.602×10⁻²¹ N west
Explanation:
Given that,
Charge of the particle, q = 8.4 C
Speed of the particle, v = 40 m/s
Magnitude of magnetic field, B = 0.33 T
Let us assumed to find the magnitude and direction of the magnetic force on the particle. Let 30.0 degrees for one, and 150 degrees for two, with a perpendicular charge. So,
If angle is 150 degrees
If angle is 90 degrees
Hence, this is the required solution.
Answer:
Explanation:
Comment
The main points are that
- The arrowheads go in opposite directions
- Displacement is measured from the origin to the arrowhead of the last vector correctly drawn.
- the tail of the second vector starts where the arrowhead of the first vector is.
Solution
40 miles west
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Displacement (30 km east)
Answer
30 km east