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Pachacha [2.7K]
3 years ago
6

A student measures the mass of an 8 cm block of brown sugar to be 12.9 g. What is the density of

Chemistry
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

0.0025g/cm³

Explanation:

Given parameters:

Mass of the brown sugar = 12.9g

dimension of the sugar = 8cm

unknown:

density of the sugar = ?

Solution

Density is defined as the mass per unit volume of a substance. The expression is given below:

      Density = \frac{mass}{volume}

We know the mass of the substance but the volume is unknown:

Volume of the brown sugar = l x bx h = 8x8x8 = 512cm³

Density of the brown sugar = \frac{12.9}{512} = 0.0025g/cm³

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Identify the balanced equation for the following reaction:<br><br> SO2(g) + O2(g) → SO3(g)
sergiy2304 [10]

Answer:  The balanced equation for the given reaction is

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side.

For example, SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)

Here, number of atoms on reactant side are as follows.

  • S = 1
  • O = 4

Number of atoms on product side are as follows.

  • S = 1
  • O = 3

To balance this equation, multiply SO_{2} by 2 on reactant side and multiply SO_{3} by 2. Hence, the equation will be re-written as follows.

2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)

Here, number of atoms on reactant side are as follows.

  • S = 2
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Number of atoms on product side are as follows.

  • S = 2
  • O = 6

Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.

Thus, we can conclude that the balanced equation for the given reaction is 2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g).

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What is the correct equilibrium constant expression for equation P2(g)
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Answer:

k = [F2]² [PO]² / [P2] [F2O]²

Explanation:

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P2(g) + 2F2O(g) ⇄ 2PO(g) + 2F2(g)

The equilibrium constant, k, is:

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or the

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or the

Two electrons

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Explanation:

<em>Choose </em><em>your </em><em>answer </em>

<em>brainlilest </em><em>me</em>

<em><u>CARRY </u></em><em><u>ON </u></em><em><u>LEARNING</u></em>

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