<h3>Answer:</h3>
Molar Mass = 56 g.mol⁻¹
<h3>Explanation:</h3>
Data Given:
Mass = 5.00 μg = 5.0 × 10⁻⁶ g
Number of Molecules = 5.38 × 10¹⁶ Molecules
Step 1: Calculate Moles of 1-Butene:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 5.38 × 10¹⁶ Molecules ÷ 6.022 × 10²³
Number of Moles = 8.93 × 10⁻⁸ Moles
Step 2: Calculate Molar Mass of 1-Butene:
As,
Mole = Mass ÷ M.Mass
Solving for M.Mass,
M.Mass = Mass ÷ Mole
Putting values,
M.Mass = 5.0 × 10⁻⁶ g ÷ 8.93 × 10⁻⁸ mol
M.Mass = 55.99 g.mol⁻¹ ≈ 56 g.mol⁻¹
Hydrogen + oxygen --> water
59,1g + x = 528g
528g - 59,1 = x
x = 468,9g
Answer:
Use either a vinegar, Borax, or bleach solution in a spray bottle to tackle the mold. Simply spray the solution on showers, baths, basins, tiles, grout, or caulking. Then use either a cleaning cloth or a toothbrush to remove the slime
Answer:
0.13 s
Explanation:
We'll begin by converting 24900 mile to metres (m). This can be obtained as follow:
1 mile = 1609.344 m
Therefore,
24900 mile = 24900 mile × 1609.344 m / 1 mile
24900 mile = 4.01×10⁷ m
Finally, we shall determine the time taken for light to circumnavigate the Earth, this can be obtained as follow:
Distance = 4.01×10⁷ m
Speed = 2.998×10⁸ m/s
Time =?
Speed = distance / time
2.998×10⁸ = 4.01×10⁷ / time
Cross multiply
2.998×10⁸ × time = 4.01×10⁷
Divide both side by 2.998×10⁸
Time = 4.01×10⁷ / 2.998×10⁸
Time = 0.13 s
Thus, it will take 0.13 s for light to circumnavigate the Earth.
C2H4 is oxidized and O2 is reduced in both reactions.
<h3>What is oxidation/reduction?</h3>
Oxidation is defined in several ways. Some of the definitions are:
- The addition of oxygen or removal of hydrogen
- Increase in the oxidation number of atoms
- Addition of electronegative or the removal of electropositive elements
Reduction, on the other hand, is defined as:
- Removal of oxygen or addition of hydrogen
- Decrease in the oxidation number of atoms
- Addition of electropositive elements or the removal of electronegative elements.
In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.
The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.
More on oxidation and reduction can be found here: brainly.com/question/3867774
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