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Answer:
x = 129.9 m
y = 30.9 m
Explanation:
When an object is thrown into the air under the effect of the gravitational force, the movement of the projectile is observed. Then it can be considered as two separate motions, horizontal motion and vertical motion. Both motions are different, so that they can be handled independently.
Given data:
= 50 m/s
Angle = 30°
Time = t = 3 s
horizontal component of velocity =
=
cos30°
= 50cos30°
= 43.3 m/s
Vertical component of velocity =
=
Sin30°
= 50Sin30°
= 25 m/s
This is a projectile motion, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.
But the vertical component of velocity varies with time and there is an acceleration along vertical direction which is equal to gravitational acceleration g.
Horizontal distance = x =
t
x = 43.3*3
x = 129.9 m
Vertical Distance = y =
t -0.5gt²
y = 25*3 - 0.5*9.8*3²
y = 75 - 44.1
y = 30.9 m
Answer:
Part a)

Part b)

Part c)

Part 4)
angular acceleration will be ZERO
Part 5)

Explanation:
Part a)
Moment of inertia of the system about left end of the rod is given as

So we have





Part b)
If force is applied to the mid point of the rod
so the torque on the rod is given as




now angular acceleration is given as



Part c)
position of center of mass of rod and sphere is given from the center of the sphere as


so moment of inertia about this position is given as

so we have




Part 4)
If force is applied parallel to the length of rod
then we have


so angular acceleration will be ZERO
Part 5)
moment of inertia about right edge of the sphere is given as

so we have



