The conversion factor between moles of calcium ion and moles of 
in would be 3 to 1.
<h3>Mole fraction</h3>
if formed from 3 carbon atoms and 3 phosphate atoms according to the equation:
Thus, there are 3 moles of calcium in every 1 mole of .
The conversion factor between moles of calcium and moles of will. therefore, be 3 to 1 or simply 3:1.
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The first one is 2
The second is 1
The third is 6
And the fourth is 3
For the first two
1. Will only give up one atom to be stable
2. Only 2 atoms
There will be a shift towards the reactants
For the reaction 2 K + F2 --> 2 KF,
consider K atomic wt. = 39
23.5 g of K = 0.603 moles, hence following the molar ratio of the balanced equation, 0.603 moles of potassium will use 0.3015 moles of F2. (number of moles, n = 0.3015)
Now, following the ideal gas equation, PV = nRT
P = 0.98 atm
V = unknown
n = 0.3015 moles
R = 82.057 cm^3 atm K^-1mole^-1 (unit of R chosen to match the units of other parameters; see the reference below)
T = 298 K
Solving for V,
V = (nRT)/P = (0.3015 mol * 82.057 cm^3 atm K^-1 mol^-1 * 298 K)/(0.98 atm)
<span>
solve it to get 7517.6 cm^3 as the volume of F2 = 7.5176 liters of F2 gas is needed. </span>
