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erastovalidia [21]
3 years ago
14

A point charge is located at the center of a thin spherical conducting shell of inner and outer radii r1 and r2, respectively. A

second thin spherical conducting shell of inner and outer radii R1 and R2, respectively, is concentric with the first shell. The flux is as follows for the different regions of this arrangement.
Φ = −10.3 ✕ 103 N · m2/C for r < r1Φ = 0 for r1 < r < r2Φ = 36.8 ✕ 103 N · m2/C for r2 < r < R1Φ = 0 for R1 < r < R2Φ = −36.8 ✕ 103 N · m2/C for r > R2

Physics
1 answer:
nadya68 [22]3 years ago
5 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  point charge is  Q_z = -0.0912 \ \mu C

The inner shell is  Q_t = 0.4168 \ \mu C

The outer shell is  Q_w = -0.6514 \ \mu C

Explanation:

From the question we are told that

    The inner radius of thin first spherical conducting shell is  r_1

    The outer radius of thin first spherical conducting shell is  r_2

    The inner radius of second thin spherical conducting shell is R_1

    The outer radius of second thin spherical conducting shell is R_2

     The magnetic flux for different region is  \phi =  -10.3 *10^3 N\cdot m^2 /C \ for  \ r < r_1

    The magnetic flux for first shell is \phi = 36 * 10^3 N \cdot m^2 /C \ for  \ r_2 < r

     The magnetic flux for second shell is \phi = -36 * 10^3 N \cdot m^2 /C \ for \  r

The magnitude of the point charge is mathematically represented as

                Q_z =  \ \phi_z * \epsilon _o

               Q_z =  -10.3*10^{3} * 8.85 *10^{-12}

               Q_z =  -9.115*10^{-8} \ C

               Q_z = -0.0912 \ \mu C

Considering the inner shell

        Q_a  = \phi_a * \epsilon _o

=>    Q_a  = 36 .8 * 10^3 * 8.85*10^{-12}

      Q_a  = 32.56*10^{-8} \ C

       Q_a  =0.326} \ \mu C

Charge on the inner shell is

       Q_t  =  Q_a  - Q_z

                    Q_t = 0.326} \ \mu   -   ( -0.0912 \ \mu)

                      Q_t = 0.4168 \ \mu C

Considering the outer  shell

     Q_y  =  \phi_y * \epsilon_o

=>    Q_y  =  -36.8 *10^{3} *  8.85*10^{-12}

        Q_y  = -32.56*10^{-8} \ C

        Q_y  = - 0.326} \ \mu C

Charge on the outer shell is

      Q_w =  Q_y - Q_z

      Q_w =-  0.326} \ \mu   -   ( -0.0912 \ \mu)

       Q_w = -0.6514 \ \mu C

 

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<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>
  • Let's draw the free body diagram of the system using the given data.
  • From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
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