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d1i1m1o1n [39]
4 years ago
6

Gina is driving her car to work, but she’s stopped at a red light. When the light turns green, she presses the gas pedal and acc

elerates (speeds up) to move the car. Which of these statements is true the moment Gina presses the gas pedal? Assume the road is flat and level.
-The net force on the car is zero in the horizontal direction.
-The net force on the car is zero in the horizontal and the vertical directions.
-The net force on the car is greater than zero in the horizontal direction.
-The net force on the car is greater than zero in the vertical direction.
-The net force on the car is less than zero in the vertical direction.
Physics
2 answers:
rusak2 [61]4 years ago
8 0
The net force of the car is greater than zero in the horizontal direction. If it were not greater thn zero, then the vehicle would remain stationary.
BaLLatris [955]4 years ago
7 0

Answer:

The net force on the car is greater than zero in the horizontal direction.

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A uniform electric field of magnitude 375 n/c pointing in the positive x - direction acts on an electron, which is initially at
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(a) The force exerted by the electric field on the electron is given by the product between the electron charge q and the intensity of the electric field E:
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Under the action of this force, the electron moves by:
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W=F \Delta x= (6\cdot 10^{-17}N)(0.032 m)=1.9 \cdot 10^{-18}J

(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:
\Delta U = U_f - U_i = -1.9 \cdot 10^{-18} J
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(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:
U_i + K_i = U_f + K_f (1)
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The electron is initially at rest, so Ki =0, and we can rewrite (1) as 
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v_f= \sqrt{ -\frac{2 \Delta U}{m_e} }= \sqrt{- \frac{2(-1.9 \cdot 10^{-18} J)}{9.1 \cdot 10^{-31} kg} } =2.04 \cdot 10^6 m/s



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