(a) The force exerted by the electric field on the electron is given by the product between the electron charge q and the intensity of the electric field E:

Under the action of this force, the electron moves by:

And the work done by the electric field on the electron is equal to the product between the magnitude of the force and the displacement of the electron. The sign has to be taken as positive, because the direction of the force is the same as the displacement of the electron, so:

(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:

Where Uf and Ui are the final and initial potential energy of the electron.
(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:

(1)
where Ki and Kf are the initial and final kinetic energies.
The electron is initially at rest, so Ki =0, and we can rewrite (1) as

and by using the mass of the electron me, we can find the value of the final velocity of the electron:
The weight should be shared between the two string equally. Therefore, tension in each string, T is;
T = 120 N/2 = 60 N
Answer:
electromagnetic waves only
Explanation:
I just took the test, Hope it helps!
Near Earth's surface, gravitational acceleration is approximately 9.81 m/s2, which means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.81 metres per second every second.