Question

How many calories would be needed to heat 5.0 lbs of copper from 22 degrees C to 80.0 degrees C? C for copper = 0.092

Answer 1

Answer:

$1.21\times 10^4$ cal would be needed to heat 5.0 lbs of copper from 22 degrees C to 80.0 degrees C.

Explanation:

$Q=m \times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for copper 0.092 cal/(g℃))  

m is the mass of water

plugging in the values

$Q=5.01 b s \times 0.092 \frac{c a l}{g^{\circ} \mathrm{c}} \times\left(80.0^{\circ} \mathrm{C}-22^{\circ} \mathrm{C}\right)$

Please Note:

1 lb = 453.592grams  

So,  

5 lbs = 5 × 453.592g  = 2268 g

$\begin{aligned} Q &=2268 g \times 0.092 \frac{c a l}{g^{\circ} \mathrm{C}} \times 58^{\circ} \mathrm{C} \\\\ Q &=12102 \mathrm{cal} \end{aligned}$

$=1.21\times10^4$ cal (Answer)