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Neporo4naja [7]
2 years ago
12

Calculate the grams of starch present in 8 drops (about 0.20 mL) of 3.0% (w/v) boiled starch solution. The unit (w/v) denotes a

weight/volume percentage.
Chemistry
1 answer:
fenix001 [56]2 years ago
8 0

Answer:

In 8 drops (0.20 mL) of the solution there is 0.0060 g of starch.

Explanation:

A 3.0% (w/v) is a weight/volume percentage that means that there are 3.0 g of solute (starch) per 100 mL of solution. Then, in 0.20 mL of solution:

0.20mL(solution).\frac{3.0g(starch)}{100mL(solution)} = 0.0060g (starch)

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What is the mass number of chlorine?
Anastasy [175]

Answer:

Explanation:

35.453 u

7 0
2 years ago
How many grams of NaOH are<br> needed to make 400. mL of<br> 1.50 M solution?
juin [17]

Answer:

24g of NaOH are required

Explanation:

Molarity, M, is an unit of concentration widely used in chemistry defined as the ratio between moles of solute (In this case, NaOH), and volume of solution in liters.

We can find the moles of NaOH and its mass with the volume and desired concentration as follows:

<em>Moles NaOH:</em>

400.0mL = 0.400L * (1.50mol / L) = 0.600 moles NaOH

<em>Mass NaOH -Molar mass: 40.0g/mol-:</em>

0.600 moles * (40.0g / mol) =

<h3>24g of NaOH are required</h3>
7 0
3 years ago
How many kg are in 50 lb luggage bag
Darya [45]
There are 0.454 kg in 1 lb

Cross multiply

0.454 kg = 1 lb
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50* 0.454 = 22.7 kg

Answer : 22.7 kg in 50 lbs
7 0
3 years ago
Read 2 more answers
A major component of gasoline is octane (C8H18). When liquid octane is burned in air it reacts with oxygen gas to produce carbon
Paraphin [41]

Answer:

The answer to your question is 0.4 moles of Oxygen

Explanation:

Data

Octane (C₈H₈)

Oxygen (O₂)

Carbon dioxide (CO₂)

Water (H₂O)

moles of water = ?

moles of Oxygen = 1

Balanced chemical reaction

                   C₈H₈  +10O₂  ⇒   8CO₂  +  4H₂O

              Reactant     Element     Products

                    8                 C                 8

                    8                 H                 8  

                   20                O               20  

Use proportions to solve this problem

                  10 moles of Oxygen ----------------- 4 moles of water

                    1 mol of Oxygen     ------------------ x

                    x = (4 x 1) / 10

                    x = 4 / 10

                    x = 0.4 moles of water

7 0
3 years ago
How many grams of oxygen are produced when 1.05 moles of hydrogen gas is<br> produced?
vivado [14]

Answer:

1.058337 grams of hydrogen and 2H2 + O2 ==> 2H2O hydrogen peroxide

mols H2 = grams/molar mass

Using the coefficients in the balanced equation, convert mols H2 to mols O2.

Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.

and it could also produce H2O water but no air but it could make other things

8 0
2 years ago
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