Answer:
If you push horizontally with a small force, static friction establishes an equal and opposite force that keeps the book at rest. As you push harder, the static friction force increases to match the force. Eventually maximum static friction force is exceeded and the book moves.
Explanation:
Answer:
Part a)
Part b)
Explanation:
As we know that the electric field between the membrane is given as
here the distance between two membranes is given as
now we know that potential difference between two membranes is given as
so we have
Part b)
Kinetic energy of helium nucleus is given as
so we have
Answer:
100 A.
Explanation:
From the question given above, the following data were obtained:
Electrochemical equivalent (Z) = 0.0012 g/C
Mass (M) = 36 g
Time (t) = 5 mins
Current (I) =?
Next, we shall determine the charge. This can be obtained as follow:
Electrochemical equivalence (Z) = 0.0012 g/C
Mass (M) = 36 g
Charge (Q) =.?
M = ZQ
36 = 0.0012 × Q
Divide both side by 0.0012
Q = 36 / 0.0012
Q = 30000 C
Next, we shall convert 5 mins to s. This can be obtained as follow:
1 min = 60 s
Therefore,
5 mins = 5 × 60
5 mins = 300 s
Finally, we shall determine the current. This can be obtained as shown below:
Charge (Q) = 30000 C
Time (t) = 300 s
Current (I) =?
Q = It
30000 = I × 300
Divide both side by 300
I = 30000 / 300
I = 100 A
Therefore, the current is 100 A.
Answer:
K = 109.1 N/m
Explanation:
From the question, the following parameters are given.
Extension e = 55 m
Force F = 6000N
According to Hooke's law,
F = Ke
Where K = spring constant.
Substitute F and e into the formula and make K the subject of formula.
6000 = K × 55
K = 6000/55
K = 109.1 N/m
Therefore, the spring constant of a bungee cord that stretches is 109.1 N/m
Density=mass÷volume
density=40.5÷15=2.7