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vagabundo [1.1K]
3 years ago
15

A bat hits a 0.150 kg baseball for 0.0880s. The balls velocity changes from 41.0 m/s left to 37.0 m/s right. How much force was

applied to the ball? Unit= N
Physics
1 answer:
Alenkasestr [34]3 years ago
7 0
From Newton's second law of motion,

F=ma
Where, F = applied force, m = mass (=0.15 kg), a = acceleration.

a= Δv/t, Δv= Change in velocity, t = time
Therefore
a = (41-37)/0.088 = 45.45 m/s^2
Then,

F = 0.15*45.45 = 6.82 N
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Uranium-235 Fission
ExtremeBDS [4]

In the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation

<h3>Balanced nuclear reaction of Uranium</h3>

The balanced nuclear reaction of uranium is determined as follows;

^{235}_{92}U\ --- > \ ^4_2He\ + \ ^{231}_{90}Th\ + \ energy

Thus, in the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation while uranium 235 is on the left hand side of the nuclear reaction equation.

Learn more about nuclear reaction here:

brainly.com/question/25387647

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4 0
2 years ago
If mass is measured in kg and acceleration is measured in m/s^2, what units would force be measured in? This unit is also know a
Vlada [557]
  • Mass=kg
  • Acceleration=m/s^2

Using Newtons second law

\\ \sf\longmapsto Force=Mass\times Acceleration

\\ \sf\longmapsto Force=kgm/s^2

\\ \sf\longmapsto Force=Newton(N)

5 0
3 years ago
AYUDA!!!!!
ZanzabumX [31]

Answer:

a) El valor de la densidad es 0.79 \frac{g}{cm^{3} } o 790 \frac{g}{cm^{3} }

b) El peso especifico es 7749.9\frac{N}{m^{3} }

Explanation:

a) La densidad se define como la propiedad que tiene la materia, ya sean sólidos, líquidos o gases, para comprimirse en un espacio determinado. En otras palabras, la densidad es una magnitud que permite medir la cantidad de masa que hay en determinado volumen de una sustancia. Entonces, la expresión para el cálculo de la densidad es el cociente entre la masa de un cuerpo y el volumen que ocupa:

d=\frac{m}{V}

En este caso:

  • masa= 237 g= 0,237 kg (siendo 1000 g= 1 kg)
  • volumen= 300 cm³= 0,0003 m³ (siendo 1 cm³= 0,000001 m³)

Reemplazando:

d=\frac{237 g}{300cm^{3} } →  d=0.79 \frac{g}{cm^{3} }

d=\frac{0,237 kg}{0,0003m^{3} }→  d=790 \frac{g}{cm^{3} }

<u><em>El valor de la densidad es 0.79 </em></u>\frac{g}{cm^{3} }<u><em> o 790 </em></u>\frac{g}{cm^{3} }<u><em></em></u>

b) El peso específico es la relación existente entre el peso y el volumen que ocupa una sustancia en el espacio.

Entonces, en este caso, siendo el peso:

P= m*g= 0,237 kg* 9,81 \frac{m}{s^{2} }= 2,32497 N

el peso especifico es calculado como:

Pe=\frac{Peso}{Volumen}= \frac{2,32497N}{0,0003 m^{3} }

Pe= 7749.9\frac{N}{m^{3} }

<u><em>El peso especifico es 7749.9</em></u>\frac{N}{m^{3} }<u><em></em></u>

8 0
3 years ago
A horizontal pull A pulls two wagons over a horizontal frictionless floor, the first wagon is 500N, the second is 2000 N. The te
MrMuchimi
<span>The force will be zero if the wagons are moving at a constant speed (i.e. not accelerating), as there is no frictional force to overcome. If the wagons are accelerating, the force will be proportional to the acceleration, and 20% of the force applied by A.</span>
5 0
3 years ago
As the frequency of a wave decreases the wavelength
alexandr402 [8]
As frequency decreases , the wavelength will increase !!

frequency= speed of light ÷ wavelength

( inverse relationship )
3 0
3 years ago
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