1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
den301095 [7]
3 years ago
5

You are a pirate working for Dread Pirate Roberts. You are in charge of a cannon that exerts a force 20,000 N on a cannon ball w

hile the ball is in the barrel of the cannon. The length of the cannon barrel is 1.84 m, and the cannon is aimed at a 50-degree angle from the ground.(1) The acceleration of gravity is 9.8 m/s2. If Dread Pirate Roberts tells you he wants the ball to leave the cannon with speed v0= 76 m/s, what mass cannon ball must you use?(2) Assuming the Dread Pirate Roberts never misses, how far from the end of the cannon is the ship that you are trying to hit (neglect dimensions of the cannon)?
Physics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

Explanation:

Force F=20,000 N

Length of barrel L=1.84 m

launch angle \theta =50

velocity at the time of launch v=76 m/s

using v^2-u^2=2 as

(76)^2=2\times a\times 1.84

a=1569.56 m/s^2

mass m=\frac{F}{a}=\frac{20,000}{1569.56}

m=12.74 kg

(2)Range of ball

R=\frac{u^2\sin 2\theta }{g}

R=\frac{(76)^2\sin 100}{9.8}

R=580.43 m

You might be interested in
For every action, there is an equal and opposite reaction.
KiRa [710]

Answer:

This is newton's 3rd law

Explanation:

3 0
3 years ago
An asteroid with a mass of 5.0 x 105 kg collides with the Earth and slides horizontally along the ground without bouncing (not a
V125BC [204]
The strength of the friction doesn't matter. Neither does the distance or the time the asteroid takes to stop. All that matters is that the asteroid has

1/2 (mass) (speed squared)

of kinetic energy when it lands, and zero when it stops.
So

1/2 (mass) (original speed squared)

is the energy it loses to friction in order to come to rest.
8 0
3 years ago
What keeps both the cars pressed down on the road? ​
mihalych1998 [28]

Answer:

Gravity

Explanation:

5 0
3 years ago
A projectile is fired directly upward from the ground with an initial velocity of 112 f/sec its distance s above the ground afte
Travka [436]

Answer:

3.48 seconds

Explanation:

At maximum height Vf=0 m/s

Vf= Vi - g*t

⇒g*t= Vi

⇒t= Vi/g

⇒t= 112/32.17 sec

⇒ t= 3.48 s

so the projectile will achieve its maximum height in 3.48 seconds.

7 0
3 years ago
When cartographers represent the three-dimensional earth in two dimensions, what is likely to occur?
Harlamova29_29 [7]
Distortion is likely to occur
7 0
4 years ago
Read 2 more answers
Other questions:
  • Which segment shows the substance changing from a gas to a liquid
    6·2 answers
  • Juan is standing on the street. An ambulance moves toward him and then passes by. What best describes the pitch that Juan heats?
    8·1 answer
  • Any object that just fits into your visual field has this angular size. Do all objects that you see this this angular size have
    13·1 answer
  • What is an intraplate quake? What causes them?
    6·1 answer
  • The characteristics of minerals: S I CC N. what does S I CC N. stand for
    12·1 answer
  • A ball is dropped from the top of a tall building. As the ball falls, the upward force of air rsistance becomes equal to the dow
    12·1 answer
  • An electron traveling parallel to a uniform electric field increases its speed from 2.0 * 107 m/s to 4.0 * 107 m/s over a distan
    12·2 answers
  • Using arrangement (a), how many rb atoms could be placed on a square surface that is 9.5 cm on a side? the diameter of a rubidiu
    14·1 answer
  • A voltage of 18 V is applied across the ends of a piece of copper wire 8 cm long. The mass of an electron is 9.11 x 10kg and its
    11·1 answer
  • A coin purse contains d dimes and q quarter's. There are 20 coins in the purse and the total value of the coins is $4.25. Which
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!