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Katena32 [7]
3 years ago
15

A go kart is traveling at a constant 13.8 meters per second around a horizontal circular track with a radius of 42.0 meters. The

Combined mass of a go kart and the driver is 143 kg. What is the magnitude of the centripetal force acting on the combined mass
Physics
1 answer:
Ivan3 years ago
4 0

Answer:

648.40N

Explanation:

Centripetal acceleration is the acceleration of an object around a circular path. Centripetal for e acting on the combined mass is expressed as:

F = ma

F = mv²/r

m is the mass of the object = 143kg

v is the linear velocity = 13.8m/s

r is the radius = 42.0m

Substitute the given parameters into the formula;

F = 143*13.8²/42

F = 27,232.92/42

F = 648.40N

Hence the magnitude of the centripetal force acting on the combined mass is 648.40N

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How many times bigger is the earth than the moon?
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vaieri [72.5K]

Answer:

B. blocks 2 & 3.

Explanation:

Block 1 has equal & opposite forces acting on it.

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6 0
3 years ago
A car is rounding a 100-m-radius curve at 25 m/s.What is the minimum possible coefficient of static friction between the tires a
Crazy boy [7]

Answer:

The minimum possible coefficient of static friction between the tires and the ground is 0.64.

Explanation:

if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :

Fc = f

m×(v^2)/(R) = μ×m×g

    (v^2)/(R) = g×μ

               μ = (v^2)/(R×g)

                  =  ((25)^2)/((100)×(9.8))

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4 0
3 years ago
A force of 50 n acts on abody of mass 5 kg .calculate the acceleration produced​
Leokris [45]

Answer:

a = 10 m/s²

Explanation:

<u><em>Given:</em></u>

Force = F = 50 N

Mass = m = 5 kg

<u><em>Required:</em></u>

Acceleration = a = ?

<u><em>Formula:</em></u>

F = ma

<u><em>Solution:</em></u>

<em>Rearranging the formula for a</em>

=> a = F/m

=> a = 50/5

=> a = 10 m/s²

8 0
3 years ago
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