What is the meaning of the state the problem ?
1 answer:
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Answer:
The work is done by the truck pulling the car 1 km is 1,212,436 J
Explanation:
Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.
So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.
In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.
The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:
Work= Force*Distante* cos (θ)
In this case:
- Force= 1,400 N= 1,400
- Distance= 1 km= 1,000 m
- θ= Angle that exists between the direction of the force and the direction= 30°
Replacing:
Work= 1,400 N* 1,000 m* cos (30°)
Work= 1,212,435. 565 Joule≅ 1,212,436 J
<u><em> The work is done by the truck pulling the car 1 km is 1,212,436 J</em></u>
<h2>Answer:</h2>
A series circuit occurs when the elements are connected along a simple path so the same current flows through all the elements. On the other hand, a parallel circuit occurs when there are two or more paths for the electricity to flow. The diagram are shown in the Figure below. We have chosen a source and resistors to illustrate this problem.
Answer:
= 1.7 cm
Explanation:
The magnification of the compound microscope is given by the product of the magnification of each lens
M = M₀
M = - L/f₀ 25/
Where f₀ and are the focal lengths of the lens and eyepiece, respectively, all values in centimeters
In this exercise they give us the magnification (M = 400X), the focal length of the lens (f₀ = 0.6 cm), the distance of the tube (L = 16 cm), let's look for the focal length of the eyepiece ()
= - L / f₀ 25 / M
Let's calculate
= - 16 / 0.6 25 / (-400)
= 1.67 cm
The minus sign in the magnification is because the image is inverted.
= 1.7 cm