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Serjik [45]
3 years ago
13

2. Earth exerts a gravitational force on the Sun and the Sun exerts a gravitational force on Earth.

Physics
1 answer:
kozerog [31]3 years ago
3 0

Answer: Earth exerts a gravitational force on the sun and the sun exerts a gravitational force on Earth

Its not very strong but strong enough to create tides. Compare the gravitational force the sun exerts on earth to the gravitational force earth exerts on the sun. ... Both because they both exert a force on each other the difference is the object with the greater mass being earth will exert a greater force.

Explanation:

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Determine the magnitude and direction of the resultant force of the following free body diagram.
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The magnitude and direction of the resultant force are approximately 599.923 newtons and 36.405°.

Explanation:

First, we must calculate the resultant force (\vec F), in newtons, by vectorial sum:

\vec F = [(-200\,N)\cdot \cos 60^{\circ}+(400\,N)\cdot \cos 45^{\circ}+300\,N]\,\hat{i} + [(200\,N)\cdot \sin 60^{\circ} + (400\,N)\cdot \sin 45^{\circ}-100\,N]\,\hat{j} (1)

\vec F = 182.843\,\hat{i} + 356.048\,\hat{j}

Second, we calculate the magnitude of the resultant force by Pythagorean Theorem:

\|\vec F\| = \sqrt{(482.843\,N)^{2}+(356.048\,N)^{2}}

\|\vec F\| \approx 599.923\,N

Let suppose that direction of the resultant force is an standard angle. According to (1), the resultant force is set in the first quadrant:

\theta = \tan^{-1}\left(\frac{356.048\,N}{482.843\,N} \right)

Where \theta is the direction of the resultant force, in sexagesimal degrees.

\theta \approx 36.405^{\circ}

The magnitude and direction of the resultant force are approximately 599.923 newtons and 36.405°.

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