Question

A box rests on the back of a truck. The coefficient of friction between the box and the surface is 0.32. (3 marks) a. When the truck accelerates forward, what force accelerates the box? b. Find the maximum acceleration the truck can have before the box slides.

Answer 1

Answer:

Part a)

here friction force will accelerate the box in forward direction

Part b)

a = 3.14 m/s/s

Explanation:

Part a)

When truck accelerates forward direction then the box placed on the truck will also move with the truck in same direction

Here if they both moves together with same acceleration then the force on the box is due to friction force between the box and the surface of the truck

So here friction force will accelerate the box in forward direction

Part b)

The maximum value of friction force on the box is known as limiting friction

it is given by the formula

$F = \mu mg$

so we have

$F = ma = \mu mg$

now the acceleration is given as

$a = \mu g$

$a = (0.32)(9.8) = 3.14 m/s^2$