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LUCKY_DIMON [66]
3 years ago
14

The minimum breaking distance d in feet for a typical vehicle can be modeled with the equation d(v) = 0.045v2, where v is the ve

hicle's speed in miles per hour. The minimum braking distance for a vehicle with new tires at optimal inflation is d(v) = 0.039v2. What kind of transformation describes this change from d(v) = 0.045v2 to d(v) = 0.039v2, and what does this transformation mean?
a.Horizontal compression by a factor of 13/15; the braking distance will be more with optimally inflated new tires than with tires having more wear.
b.Horizontal compression by a factor of 13/15; the brakin
Physics
1 answer:
xxTIMURxx [149]3 years ago
3 0
<span>To find the kind of transformation that describes this change from d(v) = 0.045v2 to d(v) = 0.039v2, find the relation between the two functions:

0.045/.039 = 45/39 = 15/13

The you have to multiply the first function times 13/15 to transform it to the second function.

When you multiply by a factor less than one you are compressiong the function vertically (if you multiply by a factor greater than 1 you are stretching vertically).

On the other hand, that the distance to stop the minimum braking distance will be smaller with the second function.

Then, the answer is that the transformation is a vertical compression by a factor of 13/15 and the braking distance will be less with optimum new tires than with tires having more wear.
</span>
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klio [65]

Answer:

P1 = 240 kPa.

Explanation:

Given the following data;

Initial volume = 0.3 m³

Final volume, V2 = 0.9 m³

Final pressure, P2 = 80 kPa

To find the initial pressure, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by the formula;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the formula, we have;

P_{1} * 0.3 = 80 * 0.9

0.3P_{1} = 72

P_{1} = \frac {72}{0.3}

P_{1} = 240

Therefore, the initial pressure of the gas is 240 kPa

3 0
3 years ago
I love buying physics toys. I recently broke out my new electromagnetic field meter and started playing with it. After turning i
harkovskaia [24]

Answer:

ionized particles from the sun.

* interactions in radiation belts.

* the friction of the planet in the solar wind

q = +9 10⁵ C

Explanation:

Due to being made up of matter, the planet Earth has a series of positive and negative charges, in general these charges should be balanced and the net charge of the planet should be zero, but there are several phenomena that introduce unbalanced charges, for example:

* ionized particles from the sun.

* interactions in radiation belts.

* the friction of the planet in the solar wind

This creates that the planet has a net electrical load

         

We can roughly calculate the charge of the planet

             E = k q / r²

             q = E r² / k

let's calculate

             q = 200 (6.37 10⁶)²/9 10⁹

              q = +9 10⁵ C

3 0
3 years ago
Den pushes a desk 400 cm across the floor. He exerts a force of 10 N for 8 s to move the desk. What is his power output? (Power:
White raven [17]

Answer:

5 W

Explanation:

The formula of the power is:

● P = W/t

W is the work and t is the time needed to do it(in seconds)

Let's calculate first the work that the force exerced:

W = Vector F . Vector d

D is the distance ( here 400 cm wich is 4 m)

Make a representation to see how are the vectors F and V.(picture below)

The vector F and d are colinear since Den is pushing the desk on the ground.

● W = 4 × 10 = 40 J

J is Joule

■■■■■■■■■■■■■■■■■■■■■■■■■■

● P = W / t

● P = 40/ 8

● P = 5 W

7 0
3 years ago
An electron moving with a velocity v⃗ = 5.0 × 107 m/s i^ enters a region of space where perpendicular electric and a magnetic fi
stiv31 [10]

Answer:

Magnetic field, B=2\times 10^{-4}\ T

Explanation:

Given that,

Velocity of electron, v=5\times 10^7\ m/s

It enters  a region of space where perpendicular electric and a magnetic fields are present.

Magnitude of electric field, E=10^4\ V/m

We need to find the magnetic field will allow the electron to go through the region without being deflected.

Magnetic force on the electron, F_m=qvB\ sin\theta.......(1)

Electric force on the electron, F = q E........(2)

From equation (1) and (2) we get:

qvB\ sin\theta=qE

B=\dfrac{E}{v}

B=\dfrac{10^4\ V/m}{5\times 10^7\ m/s}

B = 0.0002 T

or

B=2\times 10^{-4}\ T

Hence, this is the required solution.

3 0
3 years ago
A 15kg dog jumps out of a 40kg canoe. If the dogs velocity is 1.2m/s, what is the velocity of the canoe?
vivado [14]

Answer:

v = -0.45 m/s

Explanation:

Assuming the canoe was initially at rest with momentum L = 0

and that the dog's velocity is in the positive direction

conservation of momentum

0 = 15(1.2) + 40v

v = -0.45 m/s

6 0
3 years ago
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