The minimum breaking distance d in feet for a typical vehicle can be modeled with the equation d(v) = 0.045v2, where v is the ve
1 answer:
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The components of reaction at the fixed support are
,
,
,
,
,
Explanation:
Looking at the diagram uploaded we see that there are two forces acting along the x-axis on the fixed support
These force are 400 N and [ i.e the reactive force of 400 N ]
Hence the sum of forces along the x axis is mathematically represented as
=>
Looking at the diagram uploaded we see that there are two forces acting along the y-axis on the fixed support
These force are 500 N and [ i.e the force acting along the same direction with 500 N ]
Hence the sum of forces along the x axis is mathematically represented as
=>
Looking at the diagram uploaded we see that there are two forces acting along the z-axis on the fixed support
These force are 600 N and [ i.e the reactive force of 600 N ]
Hence the sum of forces along the x axis is mathematically represented as
=>
Generally taking moment about A along the x-axis we have that
=>
Generally taking moment about A along the y-axis we have that
=>
Generally taking moment about A along the z-axis we have that
=>
Answer:
The separation distance between the two charges must be 82704.2925 m
Explanation:
Given:
Two negative charges that are both q = -3.8 C
Force of 19 N
Question: How far apart are the two charges, s = ?
First, you need to get the electrostatic force of this two negative charges:
Here
k = electric constant of the medium = 9x10⁹N m²/C²
Substituting values:
Answer:
Su padre necesita aplicar una fuerza de 20 newtons en la misma dirección que la fuerza aplicada por su hija.
Explanation:
Asúmase que el baúl se mueve en una superficie horizontal. La fuerza de rozamiento dada por el problema es la fuerza de rozamiento estático máximo, se requiere una fuerza externa antiparalela a la fuerza de rozamiento estático máximo para que el baúl se empiece a mover. La ecuación de equilibrio de fuerzas horizontales sobre el baúl es:
Donde:
- Fuerza externa aplicada sobre el baúl, medida en newtons.
- Fuerza de rozamiento estático máximo, medida en newtons.
Se despeja la fuerza externa:
Si , entonces:
Si la niña solo logra ejercer una fuerza de 30 newtons, su padre necesita aplicar una fuerza de 20 newtons paralela a aquella fuerza.