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scoray [572]
3 years ago
14

Can you help me with this problem?

Chemistry
1 answer:
wolverine [178]3 years ago
4 0

Answer:

0.504 mol Ag

Explanation:

First find the moles of copper in 16g

The molar mass of Cu is: 63.546

Therefore there are .252 moles in 16g as shown by this equation:

16/63.546 = .252

The mole ratio of Cu to Ag is 1 to 2

So we can simply multiply the moles of Cu by 2/1 to find the moles of Ag

We found .252 already so we multiply it by 2 and find that the reaction produces .504 moles of Ag

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A student experimentally determines the density of a metal cube. The edge length of the cube is measured using calipers. The cub
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Answer:

10.9%.

Explanation:

The first thing to do in order to solve this question is to Determine the value for the volume of the the cube. This can be done by taking the cube root of the length of the cube;

The volume of the cube = (length of the cube)^3 = length × length × length = 1.72 × 1.72 × 1.72 =( 1.72)^3 = 5.09cm^3.

The next thing you do is to Determine the exponential density, the can be done by using the formula below;

The exponential density = mass/ volume = 55. 786/ 5.09 = 10.96 g/cm^3.

Therefore, the percent error = (true density of the cube - exponential density of the cube)÷ true density of the cube × 100.

Hence, the percent error = 12.30 - 10.96/12.30 × 100 = 10.9%.

8 0
3 years ago
Explain how to count the number of elements in a compound
valentina_108 [34]

Answer:

Using the formula cards again, add the coefficient of 2 in front of the formula and have them recalculate the number of each element and the total number of atoms in each element.

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5 0
3 years ago
Hello guys can you help me on this.​
RideAnS [48]

Answer:

1.Sulfur dioxide and nitrogen oxide

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3 years ago
A sample of gas contains 3.0L of nitrogen at 320kPa. What volume would be necessary to decrease the pressure at 110kPa
Phoenix [80]

Answer:

V_{2} = 8.92 L

Explanation:

We have the equation for ideal gas expressed as:

PV=nRT

Being:

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V = Volume

n = molar number

R = Universal gas constant

T = Temperature

From the statement of the problem I infer that we are looking to change the volume and the pressure, maintaining the temperature, so I can calculate the right side of the equation with the data of the initial condition of the gas:

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So

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P_{2}V_{2}=nRT

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clearingV_{2}

V_{2} =\frac{0.96}{P_{2} }

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V_{2} = 8.92 L

6 0
3 years ago
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