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Serggg [28]
3 years ago
10

What is a bright streak of light that results when a meteoroid burns up in earth's atmosphere?

Physics
1 answer:
CaHeK987 [17]3 years ago
4 0
<span>When a meteoroid passes through Earth's atmosphere it's traveling very fast. The friction of the air makes gets the surface so hot it begins to burn or glow red</span>
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If the merry-go-round makes one revolution in 10 seconds, what is the child’s linear speed?
Anton [14]
The child's linear speed is
              
    <em> (pi / 5) x (the child's distance from the center of the ride, in feet)</em>

                                                                                        feet per second.
5 0
3 years ago
The wind pushes a paper cub along the sand at a beach. The cup has a mass of 25 grams (= ? Kg's) and accelerates at a rate of 5
bixtya [17]

Force = (mass) x (acceleration)

= (0.025 kg) x (5 m/s²)

=   0.125 Newton
7 0
3 years ago
How to do this question
mestny [16]

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4 0
3 years ago
In an eslastic ,the momentum is_______and the mechanical energy is​
DIA [1.3K]

Answer:

In an elastic collision, the momentum is conserved and the mechanical energy is conserved too.

Explanation:

There are two types of collisions:

- Elastic collision: in an elastic collision, the total momentum before and after the collision is conserved; also, the total mechanical energy before and after the collision is conserved.

- Inelastic collision: in an inelastic collision, the total momentum before and after the colllision is conserved, while the total mechanical energy is not conserved (in fact, part of the energy is converted into other forms of energy such that thermal energy, due to the presence of frictional forces)

3 0
3 years ago
A 873-kg (1930-lb) dragster, starting from rest completes a 401.4-m (0.2509-mile) run in 4.945 s. If the car had a constant acce
Delvig [45]

To solve this problem it is necessary to apply the kinematic equations of motion.

By definition we know that the position of a body is given by

x=x_0+v_0t+at^2

Where

x_0 = Initial position

v_0 = Initial velocity

a = Acceleration

t= time

And the velocity can be expressed as,

v_f = v_0 + at

Where,

v_f = Final velocity

For our case we have that there is neither initial position nor initial velocity, then

x= at^2

With our values we have x = 401.4m, t=4.945s, rearranging to find a,

a=\frac{x}{t^2}

a = \frac{ 401.4}{4.945^2}

a = 16.41m/s^2

Therefore the final velocity would be

v_f = v_0 + at

v_f = 0 + (16.41)(4.945)

v_f = 81.14m/s

Therefore the final velocity is 81.14m/s

8 0
3 years ago
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