Answer:
0.0665 days
Explanation:
We are given;
The mean distance from the Earth's center to the moon;a1 = 385000 km
The mean distance from the Earth's center to the space craft;a2 = 6965 km
Formula for kepplers third law is;
T² = 4π²a³/GM
However, the proportion of both distances would be;
(T1)²/(T2)² = (a1)³/(a2)³
Where;
T1 is the period of orbit of the moon around the earth. T1 has a standard value of 27.322 days
T2 is the period of the space craft orbit.
Making T2 the subject, we have;
T2 = √((T1)²×(a2)³)/(a1)³)
Thus, plugging in the relevant values;
T2 = √(27.322² × 6965³)/(385000)³
T2 = 0.0665 days
1. A vector is a unit vector if its magnitude is 1. Given
and are unit vectors, while is not, since
2. Given some vector , you can get the unit vector in the same direction as
If
then the unit vectors in the direction of and , respectively, are
3.
Answer:
1: 6.637e-13 N
2: 6.637e-09 N
3: 1.335e-08 N
4: 1.335e-08 N
5: 1.456e-06 N
6: 5.839e-07 N
7: 6.673e-11 N
I'd suggest double checking these if you can.
Explanation:
Each of these you can answer by plugging the numbers into the equation
G is the gravitational constant 6.673×10⁻¹¹ N m² / kg²
So the first one would be:
I'm not going to run through showing all calculations for the rest, as you're in a rush, so to whip through them
2: 6.637e-09 N
3: 1.335e-08 N
4: 1.335e-08 N
5: 1.456e-06 N
6: 5.839e-07 N
7: 6.673e-11
Pardon the lack of superscript, I just punched these into a python console to calculate them.
Answer:
Fr = 26.83 [N]
Explanation:
To solve this problem we must use the Pythagorean theorem, since the forces are vector quantities, that is, they have magnitude and density. Therefore the Pythagorean theorem is suitable for the solution of this problem.