Answer:
1. it is symbolized as 4/2 He
: Alpha rays
2. it has the weakest penetrating power
: Alpha rays
3. It is a high-speed electron
: beta rays
4. It possesses neither mass nor charge
: gamma rays
5. it has the strongest penetrating power
: beta rays
6. its is symbolized as 0/-1e
: beta rays
7. it is the most massive of all the components: alpha rays
Explanation:
Let us consider the characteristics of each of the given rays.
α rays: These are helium nucleus so are symbolized by 
Due to two protons and two neutrons unlike beta and gamma rays these are the most massive and thus have least penetrating power among the three given rays.
β rays: These are actually high speed electrons and are symbolized as
. Due to lesser mass than alpha rays they are more penetrating than them however less penetrating than gamma rays.
γ rays : They carry no charge or mass. Due to least massive among the three rays they have highest penetrating power.
Answer:
h20 is water ash a chemical compound
Explanation:
Answer:
0.2042 M is the original concentration of
(aq) in the titrating solution.
Explanation:
Mass of
= 0.217 g
Moles of 
1 mole of
have 2 mole of As and 1 mole of
have 1 mole of As.
So, from 1 mole of
we will have 2 moles of 
Then from 0.001096 mol of
:
of 

According to reaction, 1 mole of
reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of
of cerium (IV) ions.
Volume of the acidic cerium{IV) sulfate = 21.47 ml =0.02147 L
1 mL = 0.001 L

![[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M](https://tex.z-dn.net/?f=%5BCe%5E%7B4%2B%7D%5D%3D%5Cfrac%7B0.004384%20mol%7D%7B0.02147%20L%7D%3D0.2042%20M)
0.2042 M is the original concentration of
(aq) in the titrating solution.
According to this formula when:
ΔG = ΔH - TΔS = 0
∴ ΔS = ΔH/T
∴ ΔS = n*ΔHVap / Tvap
- when n is the number of moles = mass/molar mass
when the mass = 24.1 g
and the molar mass = 187.3764 g/mol
by substitution:
∴ n = 24.1 / 187.3764g/mol
= 0.129 moles
and ΔHvap is the molar enthalpy of vaporization is 27.49 kJ/mol
and Tvap is the temperature in Kelvin = 47.6 + 273 = 320.6 K
So by substitution, we will get the ΔS the change in entropy:
∴ΔS = 0.129 mol * 27490 J/mol / 320.6 K
= 11 J/K