Explanation:
Ohm's law is used here. V = IR, and variations. The voltage across all elements is the same in this parallel circuit. (V1 =V2 =V3)
The total supply current is the sum of the currents in each of the branches. (It = I1 +I2 +I3)
Rt = (8 V)/(8 A) = 1 Ω . . . . supply voltage divided by supply current
I3 = 8A -3A -4A = 1 A . . . . supply current not flowing through other branches
R1 = (8 V)/(3 A) = 8/3 Ω
R2 = (8 V)/(4 A) = 2 Ω
R3 = (8 V)/(I3) = (8 V)/(1 A) = 8 Ω
V1 = V2 = V3 = 8 V
1 micro gram of Strontium-90 has an activity of
0.0000053 terabecquerels (TBq),
Explanation:
Given information denotes that .,one gram of Strontium-90 has an activity of 5.3 terabecquerels (TBq)
the activity of 1 micro gram is
1 gram = 1,000,000 micro gram has activities of 5.3 terabecquerels
therefore 1 micro gram has the activity of (5.3 ÷ 1,000,000 = 0.0000053 )
=
Hence ., 1 micro gram of Strontium-90 has an activity of
0.0000053 terabecquerels (TBq),
Answer:
See explanations for step by step procedures into getting answer.
Explanation:
Given that:
A fluid particle flowing along a stagnation streamline, as shown in Video V4.9 and Fig. P4.35, slows down as it approaches the stagnation point. Measurements of the dye flow in the video indicate that the location of a particle starting on the stagnation streamline a distance s = 0.8 ft upstream of the stagnation point at t = 0 is given approximately by s = 0.8e-0.61t where t is in seconds and s is in feet.(a) Factor the relation for the speed as a function of position out of the relation for speed as a function of time. What is the expression for speed V in terms of position s only
(b) For the position as a function of time given in the problem, what is the relation between the speed of the particle V and time t
(c) Symbolically, what does the derivative of position with respect to time equal.
See comolete solving at attachment