All categories

3 years ago

Which of these is a source of thermal energy inside earth

1 answer:

8 0

There's no multiple answers that you added if that's what you meant but it possibly could be Magma or radioactive decay of particles from the earths core if those two are any of the options

You might be interested in

FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions you have posted :) th

Gala2k [10]

b) accelerate to the left as much more pressure is pulling it in that direction and on the right however , there is less force .

4 0

3 years ago

When NASA was communicating with astronauts on the Moon, the time from sending on the Earth to receiving on the moon was 1.33 s.

frez [133]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description, which determine the velocity, such as the displacement of a particle as a function of time, that is to say

$v = \frac{x}{t}\rightarrow x = v*t$

Where,

x = Displacement

v = Velocity

t = Time

Our values are given as,

$v=3*10^8m/s$

$t = 1.33 s$

Replacing we have that,

$x=v*t$

$x=(3*10^8)(1.33)$

$x = 399'000.000m$

Therefore the distance from Earth to the Moon is 399.000 km

5 0

3 years ago

Determine the kinetic energy of a 55kg woman running with the velocity of 5.87m/s

Greeley [361]

The formula for kinetic energy = ½m·v<span>2

1/2 * 55 kg x 5,87 m/s ^2 = 27.5 x </span>34.4569 = <span>947.56475 Joule </span>≈ 948 J

4 0

3 years ago

STATE THE LAWS OF CONSERVATION OF MOMENTUM

dalvyx [7]

$\Huge \mid \underline {\mathcal {{{\color{purple}{Answer...}}}}} \mid$

When two bodies collide with each other in the absence of an external force, then the total final momentum of the bodies is equal to their total initial momentum.

6 0

3 years ago

A mass is attached to a vertical spring, which then goes into oscillation. At the high point of the oscillation, the spring is i

andrew-mc [135]

Answer:

0.34 sec

Explanation:

Low point of spring ( length of stretched spring ) = 5.8 cm

midpoint of spring = 5.8 / 2 = 2.9 cm

Determine the oscillation period

at equilibrum condition

Kx = Mg

g= 9.8 m/s^2

x = 2.9 * 10^-2 m

k / m = 9.8 / ( 2.9 * 10^-2 ) = 337.93

note : w = $\sqrt{k/m}$ = $\sqrt{337.93}$ = 18.38 rad/sec

Period of oscillation = $2\pi / w$

= 0.34 sec

8 0

3 years ago