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3 years ago

9

What is this ???????????

2 answers:

babymother [125]3 years ago

8 0

A, something to remember is that if the numbers are even the answer too will be even. Every time hope this helps :>

MA_775_DIABLO [31]3 years ago

7 0

Answer:

A.

Explanation:

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PLEASE ANSWER THANKS

Veseljchak [2.6K]

The answers are
1.no
2. they will attract each other
3.b
4.neither direction

8 0

3 years ago

Read 2 more answers

What is NOT a benefit of being flexible? easier to do things looser muscles tight muscles less likely to get hurt

GrogVix [38]

Answer: Looser muscle

Explanation: If your muscle are tight all the time it’s unhealthy and can cause cramps all the time rather than loose muscles that are relaxed

3 0

2 years ago

Two objects made of the same material are heated to 60 oC and 90 oC. According to

nlexa [21]

Assuming that there is in a vacuum, the two object will cool at the same rate, because the objects are made of the same material they will have the same cooling rate, assuming the surrounding temperature is the same.

4 0

3 years ago

Read 2 more answers

Breanna is standing beside a merry-go-round pushing 19° from the tangential direction and is able to accelerate the ride and her

leva [86]

To solve the problem it is necessary to apply the concepts given in the kinematic equations of angular motion that include force, acceleration and work.

Torque in a body is defined as,

$\tau_l = F*d$

And in angular movement like

$\tau_a = I*\alpha$

Where,

F= Force

d= Distance

I = Inertia

$\alpha =$ Acceleration Angular

PART A) For the given case we have the torque we have it in component mode, so the component in the X axis is the net for the calculation.

$\tau= F*cos(19)*d$

On the other hand we have the speed data expressed in RPM, as well

$\omega_f = 10rpm = 10\frac{1rev}{1min}(\frac{1min}{60s})(\frac{2\pi rad}{1rev})$

$\omega_f = 1.0471rad/s$

Acceleration can be calculated by

$\alpha = \frac{\omega_f}{t}$

$\alpha = \frac{1.0471}{9}$

$\alpha = 0.11rad/s^2$

In the case of Inertia we know that it is equivalent to

$I = \frac{1}{2}mr^2 = \frac{1}{2}(750)*(2.3)^2$

$I = 1983.75kg.m^2$

Matching the two types of torque we have to,

$\tau_l=\tau_a$

$Fd=I\alpha$

$Fcos(19)*2.3=1983.75(0.11)$

$F=100.34N$

PART B) The work performed would be calculated from the relationship between angular velocity and moment of inertia, that is,

$W = \frac{1}{2}I\omega_f^2$

$W= \frac{1}{2}(1983.75)(1.0471)^2$

$W=1087.51J$

7 0

3 years ago

A motorist drives along a straight road at a constant speed of 15 m/s. just as she passes aparked motorcycle police officer , th

allsm [11]

Explanation:

Distance traveled by motorist =(15.0m/s)t

Distance traveled by policeman =1/2(2.00m/s2)t2

(a) Intercept occurs when 15.0t =t2or t=15.0s.

(b) x(officer)=1/2(2.00m/s2)t2= 225m

4 0

1 year ago