Answer:
t=14ns
Explanation:
We make the relation between the specific access time and the memory percentage in each level, so


Average Access Time is 14 nsec.
To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.
The gas ideal law is given as,

Where,
P = Pressure
V = Volume
m = mass
R = Gas Constant
T = Temperature
Our data are given by




Note that the pressure to 38°C is 0.06626 bar
PART A) Using the ideal gas equation to calculate the mass flow,




Therfore the mass flow rate at which water condenses, then

Re-arrange to find 



PART B) Enthalpy is given by definition as,

Where,
= Enthalpy of dry air
= Enthalpy of water vapor
Replacing with our values we have that



In the conversion system 1 ton is equal to 210kJ / min


The cooling requeriment in tons of cooling is 437.2.
Answer:

Explanation:
The turbine is modelled after the First Law of Thermodynamics:

The work done by the turbine is:

The properties of the water are obtained from property tables:
Inlet (Superheated Steam)



Outlet (Superheated Steam)



The work output is:


Answer:
Explanation:
Obtain the following properties at 6MPa and 600°C from the table "Superheated water".

Obtain the following properties at 10kPa from the table "saturated water"

Calculate the enthalpy at exit of the turbine using the energy balance equation.

Since, the process is isentropic process 

Use the isentropic relations:

Calculate the enthalpy at isentropic state 2s.

a.)
Calculate the isentropic turbine efficiency.

b.)
Find the quality of the water at state 2
since
at 10KPa <
<
at 10KPa
Therefore, state 2 is in two-phase region.

Calculate the entropy at state 2.

Calculate the rate of entropy production.

since, Q = 0
