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Verizon [17]
3 years ago
6

Why VR is always less than 1 in Third class lever?​

Physics
1 answer:
Sav [38]3 years ago
3 0
Mechanical advantage of a class 3 lever is always less than 1 because the load arm is always longer than effort arm. This helps by reducing the applied force(effort).that’s your answer hope this helps you!
Have a great day!
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Acceleration Practice
Trava [24]

Answer:

0.85 m/s²

Explanation:

Acceleration is change in velocity over change in time. In mathematically, it can be expressed as:

\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{\vec v_2 - \vec v_1}{t_2-t_1}}

Our final velocity is given to be 17 m/s in 20 seconds. Initial velocity is at starting point which is 0 m/s in 0 second. Therefore:

\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{17-0}{20-0}}\\\\\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{17}{20}}\\\\\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = 0.85 \ \, \sf{m/s^2}}

Therefore, the acceleration of a horse from starting point to 17 m/s in 20 seconds is 0.85 m/s²

8 0
2 years ago
Read 2 more answers
22 points !
nordsb [41]
Evaporation. The glass of water was less full after 10 minuets because the water got evaporated




7 0
3 years ago
Which equation below represents a generic equation suggested by a graph showing a hyperbola?
ruslelena [56]

Answer:

y = k/x

Explanation:

y = k/x is a graph of a hyperbola that has been rotated about the origin.

8 0
3 years ago
Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?
GrogVix [38]

When Emmett is lifting a box vertically, the forces that must be added to calculate the total force are: the gravitational force, tension force(the force exerted by Emmett to the box and the force exerted by the box to Emmett), and air resistance force.

4 0
3 years ago
A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s
Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = \frac{m}{m+M}

calculemos

            v= \frac{0.200}{0.200+M} 0.450

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂

6 0
3 years ago
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