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LenaWriter [7]
3 years ago
11

You MUST overthink this answer!!! What is my favorite primary color GOOD EXPLANATIONS ONLY!!! (use my profile picture) USE THE C

OLORS INSIDE THE CIRCLED PORTION

Engineering
2 answers:
Helen [10]3 years ago
5 0

Answer and Explanation:

Your favorite primary color is blue because 1. blue is a primary color, 2. There is a lot of blue in the picture, and 3. You outlined the circle in blue.

Ty for the points lol.

#teamtrees #WAP (Water And Plant)

Art [367]3 years ago
3 0

Answer:

Blue

Explanation:

You want me to overthink it which is why I think the answer should be the most obvious and not the most complicated

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The purification of hydrogen gas is possible by diffusion through a thin palladium sheet. Calculate the number of kilograms of h
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Answer: 5.36×10-3kg/h

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M =JAt = -DAt×Dc/Dx

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Determine the speed of sound in air at 400 K. Also determine the Mach number of an aircraft moving in the air at a velocity of 3
Reika [66]

Answer:

\alpha = \sqrt{1.4 *0.287 \frac{KJ}{Kg K}*\frac{1000J}{1KJ} *400 K}= 400.899 m/s

Ma= \frac{310 m/s}{400.899 m/s}= 0.773

Explanation:

For this case we have given the following data:

T= 400 K represent the temperature for the air

v = 310 m/s represent the velocity of the air

k = 1.4 represent the specific heat ratio at the room

R = 0.287 KJ/ Kg K represent the gas constant  for the air

And we want to find the velocity of the air under these conditions.

We can calculate the spped of the sound with the Newton-Laplace Equation given by this equation:

\alpha = \sqrt{\frac{K}{\rho}}=\sqrt{k RT}

Where K = is the Bulk Modulus of air, k is the adiabatic index of air= 1.4, R = the gas constant  for the air, \rho the density of the air and T the temperature in K

So on this case we can replace and we got:

\alpha = \sqrt{1.4 *0.287 \frac{KJ}{Kg K}*\frac{1000J}{1KJ} *400 K}= 400.899 m/s

The Mach number by definition is "a dimensionless quantity representing the ratio of flow velocity past a boundary to the local speed of sound" and is defined as:

Ma=\frac{v}{\alpha}

Where v is the flow velocity and \alpha the volocity of the sound in the medium and if we replace we got:

Ma= \frac{310 m/s}{400.899 m/s}= 0.773

And since the Ma<0.8 we can classify the regime as subsonic.

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