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4 years ago

How can you analyze a compound formula

Physics

1 answer:

STALIN [3.7K]4 years ago

4 0

Answer:

Chemical formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound. If a compound's chemical formula cannot be reduced any more, then the empirical formula is the same as the chemical formula. Combustion analysis can determine the empirical formula of a compound, but cannot determine the chemical formula (other techniques can though). Once known, the chemical formula can be calculated from the empirical formula.

Explanation:

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A 2.00 kg, frictionless block s attached to an ideal spring with force constant 550 N/m. At t = 0 the spring is neither stretche

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Answer:

a) A = 0.603 m , b) a = 165.8 m / s² , c) F = 331.7 N

Explanation:

For this exercise we use the law of conservation of energy

Starting point before touching the spring

Em₀ = K = ½ m v²

End Point with fully compressed spring

$Em_{f}$ = $K_{e}$ = ½ k x²

Emo = $Em_{f}$

½ m v² = ½ k x²

x = √(m / k) v

x = √ (2.00 / 550) 10.0

x = 0.603 m

This is the maximum compression corresponding to the range of motion

A = 0.603 m

b) Let's write Newton's second law at the point of maximum compression

F = m a

k x = ma

a = k / m x

a = 550 / 2.00 0.603

a = 165.8 m / s²

With direction to the right (positive)

c) The value of the elastic force, let's calculate

F = k x

F = 550 0.603

F = 331.65 N

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3 years ago

Which of the following can occur when an object is accelerating?

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Answer:

Explanation:

Change in speed or direction is acceleration

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3 years ago

You drop an egg from rest with no air resistance. Which of the following statements is correct? Group of answer choices As it fa

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Answer:

As it falls, its mechanical energy is conserved, but its momentum is not conserved.

Explanation:

The mechanical energy of the egg during the fall is the sum of its potential energy and its kinetic energy:

E = U + K

As we know, mechanical energy is always conserved when there are only conservative forces acting on a system. In this case, the only force acting on the egg is the force of gravity, which is a conservative force (we are neglecting air resistance), therefore mechanical energy is conserved.

In particular, as the egg falls down, its gravitational potential energy U decreases, while its kinetic energy K increases (since its speed increases), but the sum of the two quantities, E, remains constant.

On the contrary, momentum is not conserved. In fact, momentum is given by

p = mv

where m is the mass and v is the velocity. Since the velocity of the egg increases (in magnitude) while it falls down, it means that momentum is not constant, so it is not conserved.

Why? The reason is the following: momentum is only conserved when the net external force acting on the system is zero. This is not the case: in fact, there is a net external force acting on the egg (the force of gravity), so the momentum cannot be conserved.

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A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its equilibrium position, wha

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Answer:

V = ω A sin ω t can be used to describe SHM

When sin ω t = 1 (the maximum value possible)

V = ω A at equilibrium sin ω t = 1

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