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Jet001 [13]
3 years ago
9

A radioisotope forms a stable isotope after it undergoes radioactive decay. Which is the best conclusion to draw from this state

ment?
A. It undergoes alpha decay. B. It undergoes beta decay. C. It does not participate in a decay series. D. It does not have a long half-life.
Chemistry
2 answers:
noname [10]3 years ago
8 0

Answer:

C

Explanation:

because that's just the answer:)

Black_prince [1.1K]3 years ago
3 0

Answer:

C. It does not participate in a decay series.

Explanation:

From this statement, we can deduce that a radioisotope that forms a stable isotope after it undergoes radioactive decay suggests that it does not participate in a decay series.

  • It could have emitted any form of radioactive particles which can be alpha or beta.
  • We do not know if it has a long or short half life because the value is not given.
  • But since the radioactive decay in one step produces a stable isotope, we can conclude that it did not participate in a decay series.
  • A decay series involves a radioactive decay in multiple steps.
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Read the given equation.
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<h2>Answer:</h2>

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2 years ago
List of things that you’ll use in the scientific method
MrRissso [65]

Explanation:

Make an observation

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8 0
3 years ago
Draw the reactants using the drawing tool. Keep in mind that one molecule of nitrogen has two bonded atoms, and one molecule of
ANTONII [103]

The formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1. as shown below:

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<h3>What is the equation of the formation of ammonia?</h3>

Ammonia gas is formed from the reaction between nitrogen gas and hydrogen gas.

Three moles of hydrogen gas will react with 1 mole of nitrogen gas to form 2 moles of ammonia gas.

The equation of the reaction is given below as:

N_2 + 3H_2 \rightarrow 2NH_3

Therefore, the formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1.

Learn more about ammonia gas at: brainly.com/question/7982628

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D is the correct answer

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7 0
3 years ago
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when a solution of sodium chloride is added to a solution of copper(ii) nitrate, no precipitate is observed. Write the molexular
zhuklara [117]

Explanation:

1.

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2.

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A light blue precipitate of Cu(OH)2 is formed and NaNO3 in solution.

3.

Cu(NO3)2(aq) --> Cu2+(aq) + 2NO3^-2(aq)

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4.

The reaction in both Questions 1 and 2 is called Double displacement reaction. A double-replacement reaction exchanges the cations and/or or the anions of two ionic compounds. A precipitation reaction is a double-replacement reaction in which one product is a solid precipitate (precipitated) while the other in solution.

Since the cation and anions in Qustion 1 were exchanged, the same was done for Question 2, hence the identity of the precipitate in Question 2 was got.

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