Answer:
45.9m
Explanation:
Given parameters:
Mass of the ball = 1kg
Initial velocity = 30m/s
Unknown:
Height the ball will travel = ?
Solution:
At the maximum height, the final velocity of the ball will be 0;
Using ;
V² = U² - 2gh
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
h is the height
0² = 30² - (2 x 9.8 x h)
0 = 900 - 19.6h
h = 45.9m
Answer:
1 mole of any gas at STP occupies 22.4 liters of volume. Using this information, the volume occupied by any number of moles (or grams) can be determined.
Explanation:
-III I
NH₄⁺
V -II
N₂O₅
I V -II
NaNO₃
-----------------------
-3 +5 +5
Answer:
C + O2 → CO2
Explanation:
C + O2 → CO ----------------- (1)
from equ (1) on reactant side, C has 1 mole, O has 2 moles
from equ (1) on product side, C has 1 mole, O has 1 mole
Thus, to balance the equation, O should have 2 moles
C + O2 → CO2
