Answer:
Alkane
Alkene
Alkyne
Explanation:
Alkane=1 bond (Saturated hydrocarbon)
Alkene= 2 bonds (Unsaturated hydrocarbon)
Alkyne= triple bonds (Unsaturated hydrocarbon)
Formula of Alkane = CnH2n+2
Formula of Alkene = CnH2n
Formula of Alkyne = CnH2n-2
Hi so from what I can see the pizza as a distant or and you just have to convert the grams of glucose into moles. Most teachers ask for this format
Answer: The molar enthalpy change is 73.04 kJ/mol
Explanation:
![HCl+NaOH\rightarrow NaCl+H_2O](https://tex.z-dn.net/?f=HCl%2BNaOH%5Crightarrow%20NaCl%2BH_2O)
moles of HCl= ![molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol](https://tex.z-dn.net/?f=molarity%5Ctimes%20%7B%5Ctext%20%7Bvol%20in%20L%7D%7D%3D0.415mol%2FL%5Ctimes%200.1%3D0.0415mol)
As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.
volume of water = 100.0 ml + 50.0 ml = 150.0 ml
density of water = 1.0 g/ml
mass of water = ![volume \times density=150.0ml\times 1.0g/ml=150.0g](https://tex.z-dn.net/?f=volume%20%5Ctimes%20density%3D150.0ml%5Ctimes%201.0g%2Fml%3D150.0g)
![q=m\times c\times \Delta T](https://tex.z-dn.net/?f=q%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T)
q = heat released
m = mass = 150.0 g
c = specific heat = ![4.184J/g^0C](https://tex.z-dn.net/?f=4.184J%2Fg%5E0C)
= change in temperature = ![4.83^0C](https://tex.z-dn.net/?f=4.83%5E0C)
![q=150.0\times 4.184\times 4.83](https://tex.z-dn.net/?f=q%3D150.0%5Ctimes%204.184%5Ctimes%204.83)
![q=3031.3J](https://tex.z-dn.net/?f=q%3D3031.3J)
Thus 0.0415 mol of HCl produces heat = 3031.3 J
1 mol of HCL produces heat = ![\frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ](https://tex.z-dn.net/?f=%5Cfrac%7B3031.3%7D%7B0.0415%7D%5Ctimes%201%3D73043.3J%3D73.04kJ)
Thus molar enthalpy change is 73.04 kJ/mol
If the prefix mega is added to the unit of the quantity being described, the magnitude of quantity increases by 10^{6} times i.e. 1 million times.
For Example- 1 MW = 1000000 watts
Answer: i think its A diatomic compound..
Explanation: hope i helped! sorry if im wrong!