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fomenos
3 years ago
8

A ball is thrown from ground level so as to just clear wall 4m height at distance 4m from wall and falls 14 m from wall . Veloci

ty of ball ?
Physics
1 answer:
kolbaska11 [484]3 years ago
8 0
Ok, this is a 2d kinematics problem,  the falls 14 m part is confusing, I think it means in the x direction, but you don't need it anyway.

If we know it goes 4m into the air, we know  d = 4m (height of wall), we also know the acceleration a=-9.8m/s^2 (because gravity) and that the vertical velocity when it just clears the wall will be 0 m/s, which we'll call our final velocity (Vf). Using Vf^2 = Vi^2 +2a*d, we can solve this for Vi and drop Vf because it's zero to get: Vi = sqrt(-2ad), plug in numbers (don't forget a is negative) and you get 8.85 m/s in the vertical direction. The x-direction velocity requires that we solve the y-direction for time, using Vf= Vi + at, we solve for t, getting t= -Vi/a, plug in numbers t= -8.85/-9.8 = 0.9 s. Now we can use the simple v = d/t (because x-direction has no acceleration (a=0)), and plug in the distance to the wall and the time it takes to get there v = (4/.9) = 4.444 m/s, this is the velocity in the x direction, we use Pythagoras' theorem to find the total velocity, Vtotal = sqrt(Vx^2 + Vy^2), so Vtotal = sqrt(8.85^2+4.444^2) = 9.9m/s. Yay physics!
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A wooden block is sitting on an inclined plane near the bottom. The student gave the block a flick and it moved up the inclined
sladkih [1.3K]

Answer:

The block didn't slide due to balancing of gravitational force with friction force

Explanation:

When the block was given a flick the force provided an acceleration to it and it moved up the inclined plane. when the block reached top it was expected that it would slide back but it didn't this happened because of the frictional force acting on the bottom the block which was balancing the gravitational force component along the plane and this prevented sliding back of the block.

static friction  was balancing mg*sin(theta)

fs = mg*sin(theta)

6 0
3 years ago
Two bowling balls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8 cm apart. What gravita
12345 [234]

Answer:

6.49 x 10^-8 N

Explanation:

formula is

F= G * ((m1 * m2)/r^2)

F = 6.67x10^-11 * ((6.8*6.8/.218)

F = 6.49 x 10^-8 Newtons

3 0
2 years ago
A 13-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
AysviL [449]
K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2

So, option B is your answer!

Hope this helps!

7 0
3 years ago
Through what process is carbon pulled from the atmosphere in the carbon cycle
Andrei [34K]

Carbon is pulled from the atmosphere in the carbon cycle through the process of photosynthesis. Details about photosynthesis can be found below.

<h3>What is photosynthesis?</h3>

Photosynthesis is the process whereby green plants obtain their nutrition by utilizing energy from sunlight.

Green plants absorb carbon in the form of carbon dioxide from the atmosphere and use it in the photosynthetic process.

This means that one way that carbon is removed from the atmosphere during the carbon cycle is through photosynthesis.

Learn more about photosynthesis at: brainly.com/question/1388366

#SPJ1

7 0
2 years ago
A 1100 kg car starts from rest and accelerates for 5 seconds at 4.6m/s/s how much power does the car generate
SIZIF [17.4K]

Answer:

The power expended by the car during the acceleration is 116.38KW

Explanation:

Power is a term that defines the rate at which energy is expended whenever work is done.

Power can be given as Force X velocity.

Force can be found using the formula:

F = mass X acceleration.

In this case,

F = 1100kg X 4.6m/s2

F = 5060 N

The final velocity, v of the car can be obtained from this formula:

v = u+ at

U = initial velocity = 0 (since the car started from rest)

a = acceleration = 4.6m/s2

t = time = 5 seconds

v = 0 + 4.6 X 5 = 23 m/s

Therefore, the power expended is 5060N X 23m/s=116,380W

The power expended by the car during the acceleration is 116.38KW

3 0
3 years ago
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