<span>A voltage source in a circuit provides electrical ENERGY.
In fact, a voltage source is a device (like a battery) that creates a potential difference between two points of the circuit. This potential difference allows charge carriers to move from one side of the device to the other side, flowing through the circuit, producing a current, and current is a form of electrical energy.</span>
Answer: 0.58 s
Explanation: Solution attached:
Convert first 100.0 km/h to m/s
100.0 km/h x ( 1000 m / 1 km ) x ( 1h / 3600s ) + 27.8 m/s
Use v= d / t and derive too find t:
t = d / v
= 16 m / 27.8 m/s
= 0.58 s
cancel out meters and the remaining unit is in seconds.
A<span>. speed= distance/ time
s= 4</span><span>.6m/s
d=60m
4</span><span>.6= 60/t
</span>4.6t= 60
t= 13.04 seconds
b. acceleration= (the change in velocity/speed)/(time) this is the same as a=Δv/t<span>
a= unkown
</span>Δv= (final speed - initial speed) = 3.1m/s - 4.6m/s= -1.5m/s
t=3 seconds
a=Δv/t= -1.5/3= -0.5m/s²
answer: the soccer player decelerated by 0.5m/s². This means his speed is decreasing by 0.5m/s². We know it is decreasing because the answer is negative.
c. list given information:
final velocity/speed(FS)= 0m/s
initial velocity/speed(IS)= 4m/s
distance(d)= 2m
time(t)= UNKOWN
acceleration(a)= UNKOWN
(side note: velocity and speed are almost the same thing. The difference between the two words is that velocity usually has a direction and can be negative. Speed cannot be negative. If your problems use the word "speed" I would recommend you continue to use the word "speed" as well. I wanted to clarify this so that you didn't think I was saying to divide velocity by speed.)
Equation: (final speed²)= (inital speed²)+ 2(distance)(acceleration)
FS²=IS²+2da
(0²)= (4²)+ 2(2)a
0=16+4a
-4a=16
a= -4m/s²
answer: The deceleration(decreasing acceleration) is 4m/s². This is because the speed was changing at a rate of negative 4 meters per second squared until reaching a final speed of 0m/s.
d. List given information:
Initial speed: 0m/s (we know he started from "rest" which means his IS was 0)
Final speed: UNKNOWN
time= 1.5seconds
distance= UNKOWN
acceleration= 3.1m/s²
Equation: distance= (initial speed * t) + ((1/2)*(acceleration)*(time²)
d= (IS)t + (1/2)at²
d= (0)(1.5)+ (1/2)(3.1)(1.5²)
d= 0 + 3.4785
d≈3.5 meters
Any confusion or questions? Hope this helped!
The car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.
<h3>Average velocity of the car</h3>
The average velocity of the car is calculated as follows;
x(t) = a + bt + ct2
v = dx/dt
v(t) = b + 2ct
v(0) = -10.1 m/s + 2(1.1)(0) = -10.1 m/s
v(10) = -10.1 + 2(1.1)(10) = 11.9 m/s
<h3>Average velocity</h3>
V = ¹/₂[v(0) + v(10)]
V = ¹/₂ (-10.1 + 11.9 )
V = 0.9 m/s
Thus, the car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.
Learn more about velocity here: brainly.com/question/4931057
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