Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
A penny for the scratch test (low hardness)a hand lens for inspection a peice of tile for a streak test a geologic hammer to test for cleavage of fracture and the pocket knife for the scratch test (high hardness)
Answer:
1. An encounter with the barrier
2. The distance traveled by the washer.
Explanation:
Answer:
The central and most important part of an object, movement, or group, forming the basis for its activity and growth.
Explanation:
hope this helps!
Answer:
0.625 moles MgCl₂
Explanation:
Since you were given a molarity value and volume, you should use the molarity equation to find moles. The equation looks like this:
Molarity (M) = moles / volume (L)
To find moles, you need to (1) convert mL to L (by dividing by 1,000) and then (2) plug the numbers into the formula and simplify to find moles. The final answer should have 3 sig figs as the lowest amount of sig figs in a given value is 3.
<u>Step 1:</u>
650.0 mL / 1,000 = 0.6500 L
<u>Step 2:</u>
Molarity = moles / volume
0.962 M = moles / 0.6500 L
(0.962 M) x (0.6500 L) = moles
0.625 = moles
