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scZoUnD [109]
3 years ago
6

Write a summary paragraph explaining limiting and excess reactants and how you can tell which is which.

Chemistry
1 answer:
4vir4ik [10]3 years ago
3 0
In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents. The reagent that is completely used up or reacted is called the limiting reagent, because its quantity limits the amount of products formed. The limiting reactant or limiting reagent is the first reactant to get used up in a chemical reaction. Once the limiting reactant gets used up, the reaction has to stop and cannot continue and there is extra of the other reactants left over. Those are called the excess reactants. The reactant that produces a lesser amount of product is the limiting reagent. The reactant that produces a larger amount of product is the excess reagent. To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.
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Which of the following is an acid?
shusha [124]
Bleach Hope this helps have a good day
8 0
3 years ago
A 12.0 g sample of a metal is heated to 90.0 ◦C. It is then dropped into 25.0 g of water. The temperature of the water rises fro
deff fn [24]

Answer:

The specific heat of the metal is 0.34 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 12.0 grams

Mass of the water = 25.0 grams

Initial temperature of the metal = 90.0 °C

Initial temperature of the water = 22.5 °C

Final temperature = 25 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of the metal

Qlost = Qgained

Q = m*c*ΔT

Qmetal = -Qwater

m(metal) *c(metal)* ΔT(metal) = -m(water) * c(water) *ΔT(water)

⇒ with mass of metal = 12.0 grams

⇒ with c(metal) = TO BE DETERMINED

⇒ with ΔT(metal) = T2 - T1  = 25.0°C - 90.0 °C = -65.0 °C

⇒ with mass of water = 25.0 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.0 - 22.5 °C = 2.5 °C

12.0 * c(metal) * -65.0 °C = -25.0g * 4.184 J/g°C * 2.5°C

-780.0 * c(metal) = -2615  ( 2.6*10^3 with sig figs)

c(metal) = 0.335 (=0.34 with sig figs)

The specific heat of the metal is 0.34 J/g°C

3 0
3 years ago
according to john dalton’s observations, when elements combine in a compound, a. the ratio of their masses is always the same. b
yawa3891 [41]

<u><em>Answer:</em></u>

  • The correct answer is a.
  • The ratio of their masses is always the same

<u><em>Explanation:</em></u>

  • Dalton law was based on law of conservation of masses and law of conservation definite proportional. So here , it is cleared that the ratio of their masses should be always same.
8 0
3 years ago
Read 2 more answers
What does D represent?
yuradex [85]

Answer:

The energy of the reactants.

3 0
3 years ago
Calculate the molarity of each solution. 28.33 g c6h12o6 in 1.28 l of solution
QveST [7]
Molarity is number of moles of solute in 1 L of solution
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volume of solution is 1.28  L
since molarity is number of moles in 1 L
the number of moles in 1.28 L - 0.1574 mol
therefore number of moles in 1 L - 0.1574 mol / 1.28 L = 0.123 M
molarity is 0.123 M

4 0
3 years ago
Read 2 more answers
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