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Gekata [30.6K]
2 years ago
13

When a 40V battery is connected across an unknown resistor there is a current of 100 ma  in the circuit.

Physics
2 answers:
vampirchik [111]2 years ago
6 0
400 ohms because 4 times 100
amm18122 years ago
4 0

Answer:

R = 400 ohms.

Explanation: Voltage of the battery, V = 40 V. Current in the unknown resistor I = 100mA. Let R is the resistance of the resistor. It can be calculated using Ohm's law it gives the relationship between the voltage, resistance and current.. R = V/I. R = 40 V/10-¹A. R = 400 Ohm's. So, the value of the resistance of the resistor is 400 Ohm's

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Two resistors are connected in parallel two equivalent resistance is 3,75 ohm if one resistor has a resistance of 10ohm what is
yawa3891 [41]

Answer:

6 Ω

Explanation:

Two resistors in parallel  = 3.75   ohm when one is 10 ...

r1 * r2 / (r1+r2) = 3.75

10 r2 / ( 10 + r2 )= 3.75

10 r2 = 37.5 + 3.75r2

6.25 r2 = 37.5

r2 = 6Ω

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As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr
zubka84 [21]

Answer:

894.12\ \text{N}

284.013\ \text{J}

Explanation:

U = Energy = 76 J

x = Displacement of spring = 0.17 m

k = Spring constant

Energy is given by

U=\dfrac{1}{2}kx^2\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 76}{0.17^2}\\\Rightarrow k=5259.51\ \text{Nm}

Force is given by

F=kx\\\Rightarrow F=5259.51\times 0.17\\\Rightarrow F=894.12\ \text{N}

The magnitude of force must you apply to hold the platform is 894.12\ \text{N}.

Now x=0.17+0.2=0.37\ \text{m}

U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 5259.51\times 0.37^2\\\Rightarrow U=360.013\ \text{J}

Additional energy

360.013-76=284.013\ \text{J}

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