Answer:
-True - True - true - false -false - false
Explanation:
- True The flow depends only on the charge into the surface, not on the relative position
- True The two vectors are radial, so their relative direction do not changes
- True It just depends on the charge inside
- False, it only depends on the charge, not on the form from the integration surface
- False, because if it has a load inside it can be considered in the center, but if the load is outside the flow lines change direction with respect to the surface
- False The flow depends only on the load inside, not on its position
Nice couch lol
and aluminum I think
Answer:
the angular acceleration of the car is 1.5 rad/s²
Explanation:
Given;
initial angular velocity, 
= 10 rad/s
final angular velocity, 
= 25 rad/s
time of motion, t = 10 s
The angular acceleration of the car is calculated as follows;
Therefore, the angular acceleration of the car is 1.5 rad/s²
Answer:
v = -v₀ / 2
Explanation:
For this exercise let's use kinematics relations.
Let's use the initial conditions to find the acceleration of the electron
v² = v₀² - 2a y
when the initial velocity is vo it reaches just the negative plate so v = 0
a = v₀² / 2y
now they tell us that the initial velocity is half
v’² = v₀’² - 2 a y’
v₀ ’= v₀ / 2
at the point where turn v = 0
0 = v₀² /4 - 2 a y '
v₀² /4 = 2 (v₀² / 2y) y’
y = 4 y'
y ’= y / 4
We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.
v² = v₀² -2a y’
v² = 0 - 2 (v₀² / 2y) y / 4
v² = -v₀² / 4
v = -v₀ / 2
We can see that as the system has no friction, the arrival speed is the same as the exit speed, but with the opposite direction.
