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3 years ago

Stirring increases the rate of dissolution because it?

1 answer:

6 0

Answer would be B. Stirring allows parts of the solution to come into contact with what you are trying to stir into a “new solution”. Think of it like shaking a smoothie bottle when you see separation happen after not touching the smoothie for a while :)

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Improvements in which area would help reduce the possibility of damage to the environment when using uranium as a fuel?

kogti [31]

Answer:

A is the answer; 'more-efficient extraction techniques

Explanation:

I just took the test and got it right :D

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3 years ago

Electron configuration for Lithium.

Ira Lisetskai [31]

The answer to problem is [He] 2s1. Hope it helps

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4 years ago

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What do genotype will appear in boxes 2 and 3?

VMariaS [17]

Tt is the genotype that will appear in boxes two and three.

If you look at the column and row that intersect to form boxes two and three, you will see that they are T and t. That is the best way I can describe it, sorry if it’s confusing.

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3 years ago

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Because of the high number of hydrogen bonds, water exhibits ____________ , meaning the molecules cling together. under ordinary

Katena32 [7]

Answer: 1) "cohension" ;

2) "liquid" .
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3 years ago

The expected o-c-h angle in this molecule is degrees. the expected hybridization at the central carbon is

WINSTONCH [101]

Each neutral carbon atom contains four valence electrons and may form up to four electron domains. Possible hybridizations include

$sp^{3}$ , four electron domains, as in ethane $\text{C}_2\text{H}_6$
$sp^{2}$ , three electron domains, as in ethene $\text{C}_2\text{H}_4$
$sp$ , two electron domains, as in ethyne $\text{C}_2\text{H}_2$

Molecules of each of the three hybridization demonstrate spatial configurations that would maximizes the separation between the electron domains.

Carbon atoms with a $sp^{3}$ hybridization would demonstrate a tetrahedral configuration with a bond angle of approximately $109.5\textdegree{}$
Carbon atoms with a $sp^{2}$ hybridization would demonstrate a triangular planar configuration with a bond angle of $120\textdegree{}$
Carbon atoms with a $sp$ hybridization would demonstrate a linear configuration with a bond angle of $180\textdegree{}$

Bond angles are characteristic of the spatial configuration of electron domains and identifies the hybridization of the central carbon atom.

Note that each hydrogen atom contains only one valence electron and would form only single bonds. It takes two valence electrons for oxygen atoms to achieve an octet such that each oxygen form only two bonds at a single time. Therefore given the fact that the carbon is bonded to both hydrogen and oxygen, only the following hybridizations are possible

$sp^{3}$ in which the oxygen atom forms a carbon-oxygen double bond with the central carbon atom;
$sp^{2}$ in which the oxygen atom forms a single bond with the central carbon atom and with a second atom.

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4 years ago