Explanation:
i think the answer might be D
Answer:
2.5 %
Explanation:
Considering:
Or,
Given :
For 
:
Molarity = 0.2850 M
Volume = 63.30 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 63.30 × 10⁻³ L
Thus, moles of :
Moles of = 0.0180405 moles
Moles of = Moles of 
Thus, Moles of = 0.0180405 moles
Molar mass of = 35.453 g/mol
Mass = Moles * Molar mass = 0.0180405 moles * 35.453 g/mol = 0.6396 g
Volume of sea water = 25.00 mL
Density = 1.024 g/mL
Density = Mass / Volume
Mass = Density * Volume = 1.024 g/mL * 25.00 mL = 25.6 g
<u>Mass percent of Cl⁻ = 2.5 %</u>
Answer:
For enlightenment, development and making people understand the usefulness of the product
Answer:
(a) Pair 1: H₂S and HS⁻
Pair 2: NH₃ and NH₄⁺
(b) Pair 1: HSO₄⁻ and SO₄⁻
Pair 2: NH₃ and NH₄⁺
(c) Pair 1: HBr and Br⁻
Pair 2: CH₃O⁻ and CH₃OH
(d) Pair 1: HNO₃ and NO₃⁻
Pair 2: H₃O⁺
Explanation:
When an acid loses its proton (H⁺), a conjugate base is produced.
When a base accepts a proton (H⁺), it forms a conjugate acid.
(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.
NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺
(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.
The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.
(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.
CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.
(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.
H₂O gains a proton to form the conjugate acid H₃O⁺.
