Answer:
it went under the process known as crystalization
Explanation:
am a chemist
Answer:
B
Explanation:
I took the test and GOT an A
Answer: 25.89g of O2 (g)
Explanation:
We begin by finding the molar mass of compounds of interest in the given equation. 2 KClO3 ⟶ 2 KCl + 3 O 2
1 mole of KCLO3 = 39 .10 + 35.5 + (3x16) = 122.55g, 2Moles would be 2 x 122.5 = 245.1g
1 mole Oxygen gas = 32g, 3 moles would be, 3 x 32= 96g
According to the equation;
245.1g of KCLO3 produces 96g of O2 (g)
If 1g of KCLO3 produces 96÷245.1 of O2 (g) from heating.
66.1g of KCLO3 would produce; 96÷245.1 x 66.1 = 25.89g of O2 (g) from heating.
Same here no one answers my questionssssss
M=0.3 kg
h=1.8 m
g=9.81 m/s²
E=mgh
E=0.3*9.81*1.8=5.3 J
