Question

A vehicle starts to move from rest and attains an acceleration of 0.8 m/sec square in 10 seconds. Calculate the final velocity and distance covered by vehicle within that time.​

Answer 1

Answer:

final velocity=8m/s

distance covered=40 m

Explanation:

$u = 0 \\ a = 0.8 \\ t = 10 \\ now \\ a = \frac{v - u}{t} \\ 0.8 = \frac{v - 0}{10} \\ 8 = v - 0 \\ v = 8 \\ again \\ d = ut + \frac{1}{2} a {t}^{2} \\ = 0 \times 10 + \frac{1}{2} \times 0.8 \times {10}^{2} \\ = 0 + 1 \times 0.4 \times 100 \\ = 0 + 40 \\ = 40$