Answer:
The correct answer is 160.37 KJ/mol.
Explanation:
To find the activation energy in the given case, there is a need to use the Arrhenius equation, which is,
k = Ae^-Ea/RT
k1 = Ae^-Ea/RT1 and k2 = Ae^-Ea/RT2
k2/k1 = e^-Ea/R (1/T2-1/T1)
ln(k2/k1) = Ea/R (1/T1-1/T2)
The values of rate constant k1 and k2 are 3.61 * 10^-15 s^-1 and 8.66 * 10^-7 s^-1.
The temperatures T1 and T2 are 298 K and 425 K respectively.
Now by filling the values we get:
ln (8.66*10^-7/3.61*10^-15) = Ea/R (1/298-1/425)
19.29 = Ea/R * 0.001
Ea = 160.37 KJ/mol
I'm guessing you mean O2 gas? This is an elemental compound. It can't be a mixture because it is composed of only 1 element. Hope I helped!
Answer: C REDUCTION
Explanation:
Guessed after knowing oxidation isn't the answer. Got right
The two correct options are Poison dart frog and Boa constrictor. Both these organisms are pure carnivores which are also known as pure meat eaters in the food web. Carnivores are organisms in the food chain that only meat-eaters and never take any type of vegetation in their diet.
Explanation:
- A Poison dart frog purely survives on meat (meat- eater).
- Long sticky tongues are used to catch their prey such as ants, flies, insects.
- Since they produce high toxin levels, it has very few predators in the wild.
- Boa constrictor is also an organism that eats only meat.
- While they are young they eat prey like rats, squirrels and mice.
- The type of attack used by a boa constrictor is an ambush attack type. It attacks its preys using the surprise factor.
Answer:
The 
for the reaction 
will be 4.69.
Explanation:
The given equation is A(B) = 2B(g)
to evaluate equilibrium constant for
![K_c=[B]^2[A]](https://tex.z-dn.net/?f=K_c%3D%5BB%5D%5E2%5BA%5D)
= 0.045
The reverse will be 
Then, ![K_c = \frac{[A]}{[B]^2}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5BA%5D%7D%7B%5BB%5D%5E2%7D)
= 
= 
The equilibrium constant for will be
= 4.69
Therefore, for the reaction will be 4.69.
