The magnitude (in N) of the electric force that one particle exerts on the other is A. F=107.6nN.
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
Experiments with electric charges have shown that two charged objects exert electrical forces on each other. The magnitude of the force is linearly proportional to the net charge of each object and inversely proportional to the square of the distance between the objects.
Coulomb's law for calculating electrostatic forces. This force arises from the interaction between two charged objects (or point charges), the magnitude of which is calculated by F = kQ1Q2r2 F = k Q 1 Q 2 r2.
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Answer:
F = 1958.4 N
Explanation:
By volume conservation of the fluid on both sides we can say that volume of fluid displaced on the side of the car must be equal to the volume of fluid on the other side
so we have
so the car will lift upwards by distance 1.2 m and the other side will go down by distance 15.55 m
So here the net pressure on the smaller area is given as
excess pressure exerted on the smaller area is given as
now the force required on the other side is given as
6.5 meters per second mutiplied by 3 seconds and you get 19.5 meters
A student uses a meter to measure 120 coulombs flowing through a circuit in 60 seconds. The electric current in this circuit will be 2 A
Current is a flow of electrical charge carriers, usually electrons or electron-deficient atoms. The common symbol for current is the uppercase letter I. The standard unit is the ampere, symbolized by A.
current = charge / time
given
time = 60 seconds
charge = 120 Coulombs
current = Q / T = 120 / 60 = 2 A
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Answer:If the kinetic and potential energy in a system are equal, then the potential energy increases. ... Stored energy decreases. Energy of motion decreases. Total energy decreases
Explanation:
