Answer:
Explanation:
a)
Ff = μmgcosθ
Ff = 0.28(1600)(9.8)cos(-84)
Ff = 458.9217...
Ff = 460 N
b) ignoring the curves required at top and bottom which change the friction force significantly, especially at the bottom where centripetal acceleration will greatly increase normal forces and thus friction force.
W = Ffd
W = 458.9217(-49.4/sin(-84)
W = 22,795.6119...
W = 23 kJ
c) same assumptions as part b
The change in potential energy minus the work of friction will be kinetic energy.
KE = PE - W
½mv² = mgh - (μmgcosθ)d
v² = 2(gh - (μgcosθ)(h/sinθ))
v = √(2gh(1 - μcotθ))
v = √(2(9.8)(49.4)(1 - 0.28cot84))
v = 30.6552...
v = 31 m/s
From the solution that I have done, the wavelength in the question that we have is 31.88 cm
<h3>How to solve for the wavelength</h3>
The frequency in the question is given as 40/30 = 1.33 hz
Next we have to solve for V
= 425/10
= 42.5 cm/s
v = frequency * wavelength
we have to put in the values in the formula. This would be
42.5 = 1.33 x wavelength
we have to divide through by 1.33 to get the wavelength. This would be
42.5/1.333 = wavelength
31.88 cm = wavelength
Hence we can say that the wavelength in the question that we have here is 31.88 cm
Read more on wavelength here:
brainly.com/question/10728818
#SPJ4
Answer:
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
Explanation:
For this exercise let's use the relationship between momentum and momentum.
I = F t = Δp
in this case the final velocity is zero
F t = 0 -m v₀
F = m v₀ / t
in order to answer the question we must assume that the two vehicles have the same mass and speed
concrete barrier
F₁ = -p₀ / 0.1
F₁ = - 10 p₀
barrier collapses
F₂ = -p₀ / 1
let's look for the relationship of the forces
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
