41.2 = h-1/2g(t-1)^2
<span> {-h = -1/2gt^2-1/2g+g*t-41.2
</span><span> {h = 1/2gt^2
</span><span> summing them up
</span><span> 0 = -1/2g+g*t-41.2
</span><span> 41.2 +4.9 = g*t
</span><span> t = 46.1/9.8 = 4.70 sec
</span><span> h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m </span>
Answer: A. spin very rapidly when they're young.
Explanation:
A pulsar (pulsating star) is a neutron star that emits very intense jets of electromagnetic radiation in the range of radio waves, X-rays or gamma rays, at short and periodic intervals due to its intense magnetic field that induces this emission.
One of its main charateristics is its rapidly rotation (spin) when this star is young. So, as the star spins, beams of radio radiation from it sweep through space. If one of these beams points toward the Earth, we observe a <u>pulse</u>.
This is possible when the magnetic pole of the star "points" to the Earth and then stops pointing a thousandth of a second later due to the fast rotation of the star, appearing again when the same pole returns to point towards Earth.
C because it’s not a or B so 50/50 c or d and d is def not the answer so c
Answer:
1.07 m
Explanation:
x = Compression of the spring
k = Spring constant = 53 N/m
Initial length = 18 cm
P = Kinetic energy
K = Kinetic energy
At the lowest point of the mass the energy conservation is as follows
![P_{ig}+P_{is}+K_i=P_{fg}+P_{fs}+K_f\\\Rightarrow mgx+0+0=mgx+\frac{1}{2}kx^2\\\Rightarrow x=\frac{2mg}{k}\\\Rightarrow x=\frac{2\times 2.4\times 9.81}{53}\\\Rightarrow x=0.89\ m](https://tex.z-dn.net/?f=P_%7Big%7D%2BP_%7Bis%7D%2BK_i%3DP_%7Bfg%7D%2BP_%7Bfs%7D%2BK_f%5C%5C%5CRightarrow%20mgx%2B0%2B0%3Dmgx%2B%5Cfrac%7B1%7D%7B2%7Dkx%5E2%5C%5C%5CRightarrow%20x%3D%5Cfrac%7B2mg%7D%7Bk%7D%5C%5C%5CRightarrow%20x%3D%5Cfrac%7B2%5Ctimes%202.4%5Ctimes%209.81%7D%7B53%7D%5C%5C%5CRightarrow%20x%3D0.89%5C%20m)
At its lowest position the mark on the ruler will be
![x_f=0.18+0.89\\\Rightarrow x_f=1.07\ m](https://tex.z-dn.net/?f=x_f%3D0.18%2B0.89%5C%5C%5CRightarrow%20x_f%3D1.07%5C%20m)
The spring line will end up at 1.07 m
Answer:
C. 640
Explanation:
The minimum force would occur in a frictionless environment and act parallel to any abutting surface.
F = ma = 160(4) = 640 N