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suter [353]
4 years ago
10

A weather balloon is floating at a constant height above the earth when it releases a pack of instruments. If the pack hits the

ground with a velocity of –73.5 m/s, how far did the pack fall?
a 7.45 m
b -7.45 m
c 275 m
d - 275 m
Physics
1 answer:
andrezito [222]4 years ago
4 0

Answer:

c 275 m

Explanation:

Given parameters:

Final velocity  = 73.5m/s

Unknown:

Height of fall  = ?

Solution:

Since the body is falling from rest, U = 0 or initial velocity is 0m/s. Then we use one of the kinematics equation to solve this problem.

           V²   = U²  + 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

           73.5²   = 0²  +  (2 x 9.8 x h)

         5402.25 = 19.6h

                h = 275.6m

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fredd [130]

Answer:

The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".

Explanation:

Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.

Let's look at the speed of the car

F = m a\\\\a =\frac{F}{m}

We use movies and find lips

\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t

The moment is defined by

\to p = m v

The moment change

\Delta p = m v - m v_0

Let's replace the speeds in this equation

\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0  + F t - m v_0\\\\\Delta p = F t

They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.

5 0
3 years ago
A deer is running from a mountain lion when it encounters a fence that is 1.50 m high. Seeing the fence, the deer jumps, leaving
Novosadov [1.4K]

Answer:

Explanation:

Given

Initial Velocity (u)=13 m/s

angle=29^{\circ}

distance between fence and deer=2.5 m

We consider deer jump similar to projectile motion

equation of trajectory

y=xtan\theta -\frac{gx^2}{2u^2(cos\theta )^2}

y=2.5tan(29)-\frac{9.8\times 2.5^2}{2\times 13^2\times (cos29)^2}

y=1.385-0.2368=1.148 m

Thus deer will cross the fence with an difference in its jump and fence

1.5-1.148=0.351 m

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{13^2\times (sin29)^2}{2\times 9.8}

h_{max}=2.02 m

so deer rises during when it is over fence

8 0
4 years ago
Okay, I have three more questions.
Blababa [14]
When a liquid or a gas is heated, it expands and becomes less dense, so it rises, while the cooler, denser liquid or gas sinks. (Not sure if this helps but this is what I hit)
5 0
3 years ago
Read 2 more answers
What do u do if ur baby sitting and the kid falls down the stairs and breaks his nose. Should I tell the parents or no? What do
igor_vitrenko [27]

Answer:

Call the parent's for the safety of the baby

Explanation:

5 0
4 years ago
Read 2 more answers
If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in
Elza [17]

Answer:

The reflected resistance in the primary winding is 6250 Ω

Explanation:

Given;

number of turns in the primary winding, N_P = 50 turns

number of turns in the secondary winding, N_S = 10 turns

the secondary load resistance, R_S = 250 Ω

Determine the turns ratio;

K = \frac{N_P}{N_S} \\\\K = \frac{50}{10} \\\\K = 5

Now, determine the reflected resistance in the primary winding;

\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms

Therefore, the reflected resistance in the primary winding is 6250 Ω

6 0
4 years ago
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